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3 years ago

Which are equivalent to 2 1/3 x 3/14? Check all that apply.

Mathematics

1 answer:

Usimov [2.4K]3 years ago

3 0

I think is 1/2 sorry if I’m wrong

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

Whats the answer to 0.8 divided by 697.04 show work please.

Varvara68 [4.7K]

Answer:

.00114771

hope this helps, good luck :)

4 0

2 years ago

I NEED HELP ASAP PLEASE!! I WILL AWARD BRAINLIEST

Irina-Kira [14]

9514 1404 393

Answer:

x ≥ 7
54 -6m
y -x

Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

108. |x -7| = x -7 . . . . . true for x-7≥0

x ≥ 7 . . . . makes the statement true

1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

54 -6m . . . . . simplified form for m < 9

1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

6 0

3 years ago

Jhon can solve 6 math problems in 20 minutes while another student, Juaqine, can solve the same 6 math problems at a rate of 1 p

ASHA 777 [7]

Answer:

Jhon

Step-by-step explanation:

At the rate of 4 minutes per problem, it take Juaqine ...

(4 min/prob)×(6 prob) = 24 min

to solve the problems.

That is more time than it takes Jhon, so Jhon is faster.

3 0

3 years ago

Find the circumference of the circle to the nearest tenth. Use 3.14 for pi.

katrin2010 [14]

Answer:157 m

Step-by-step explanation:you need to multiply 3.14*25*2

3 0

3 years ago