1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MA_775_DIABLO [31]
3 years ago
7

For the following reactions, predict the products and write the balanced formula equation, complete ionic equation, and net ioni

c equation. If no precipitate forms, write "No reaction:" a. Hg2(NO3)2(aq) + CuSO4(aq) b. Ni(NO3)2(aq) + CaCl2(aq) c. K2CO3(aq) + MgI2(aq) d. Na2CrO4(aq) + AlBr3(aq)
Chemistry
1 answer:
stealth61 [152]3 years ago
6 0

Answer:

.

Explanation:

To predict the products of these reactions we need to know the kind of reactions. All these reactions are double replacement reaction. In these kinds of reactions, the products will be the result of exchanging ions in the reactants. So, the first step is to identify the ions.  

For the reaction, we have Hg2(NO3)2 and CuSO4.  We have the ions Hg+1,  NO3-1,   Cu+2 and SO4-2  

The way to make this exchange is putting together positive in one species with the negative of the other species. Following that rule we have

Hg^{+1}  - - -  (SO_{4})^{-2}[/text]
the oxidation number will tell you the subscript for each species in the compound. In this case, is Hg2(SO4)  [tex]Cu^{+2} - - -  (NO_{3})^{-1}  - - ->  Cu(NO_{3})_{2} [/text]  
So, the products for this reaction will be
  [tex]Hg_{2} (NO_{3})_{2}(aq) + CuSO_{4}(aq)  -->  Hg_{2}SO_{4} + Cu(NO_{3})_{2}[/text]

After this, we proceed to balance the equation. For this, we check that we have the same number of each element on both sides of the equation. In this case, we can see that we have the same number, so the equation is balanced.  Finally, we check the rules of solubility to see if the species are soluble in water or not. In this case sulfates area always soluble except for mercury so Hg2(SO4) precipitates in the solution (pre). Nitrates are always soluble so Cu(NO3)2 is soluble (aq)  
[tex] Hg_{2}(NO_{3})_{2}(aq) + CuSO_{4}(aq)  - -> Hg_{2}SO_{4} (pre) + Cu(NO_{3})_{2}(aq)

The complete ionic equation allows to show which of the reactants or products exist primarily as ions.  For this reaction this will be:

2Hg^{+1}(aq)  + 2(NO_{3})^{-1}(aq) + (SO_{4})^{-2}(aq)  + Cu^{+2}(aq)    -->  Hg_{2}SO_{4} (pre)+ Cu^{+2}(aq)    + (NO_{3})^{-1}(aq) [/text]

To get net ionic equation we take away the ions that did not participate in the reactions. In other words the ones that are the same on both sides in the equation. In this case we see that [tex] Cu^{+2}(aq)   and  (NO_{3})^{-1}(aq) [/text] are the same on both sides so those ions are not include in the net ionic equation.  This is:
[tex] 2Hg^{+1}(aq)  + (SO_{4})^{-2}(aq)  -->  Hg_{2}SO_{4} (pre) [/text]

B [tex] Ni(NO_{3})_{2}(aq) + CaCl_{2}(aq)

ions (1) Ni^{+2}  and (NO_{3})^{-1}

ions (2) Ca^{+2} and Cl^{-1}

Exchanging  

Ni^{+2}  ---- Cl^{-1}  -->  NiCl_{2}  

Ca^{+2} ---  (NO_{3})^{-1}  -->  Ca(NO_{3})_{2}  

Products  

Ni(NO_{3})_{2}(aq) + CaCl_{2}(aq) -->  NiCl_{2}  + Ca(NO_{3})_{2}  

The equation is already balanced

Chlorides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. NiCl2 is soluble (aq)

Nitrates are always soluble. Ca(NO3)2 is soluble (aq)  

Since both compounds are soluble, we can say that there is not reaction.

Complete ionic equation  

Ni^{+2}(aq) + 2(NO_{3})^{-1}  (aq) + Ca^{+2}(aq) + 2Cl^{-1}(aq) - - > Ni^{+2}(aq) + 2(NO_{3})^{-1}  (aq) + Ca^{+2}(aq) + 2Cl^{-1}(aq)

Net ionic equation:

The ions in both sides of the equation are the same so all of them are cancelled and we cannot get a net ionic equation this explains why there is no reaction in this case.  

C K_{2}CO_{3}(aq) + MgI_{2}(aq)

Ions(1) K^{+1}  and (CO_{3})^{-2}

Ions(2) Mg^{+2}  and l^{-1}

Exchanging  

K^{+1}  ---  l^{-1}  - - >  KI

Mg^{+2}  ---  (CO_{3})^{-2}  - - >  Ca(CO_{3})

Products  

K_{2}CO_{3}(aq) + MgI_{2}(aq) - ->   Kl + MgCO_{3}  

The equation is not balanced

Balance equation is  

K_{2}CO_{3}(aq) + MgI_{2}(aq) - ->  2Kl (aq) + MgCO_{3} (pre)  

iodides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. KI is soluble (aq)

carbonates are always insoluble except group 1 cations. MgCO3 is insoluble (pre)

complete ionic equation  

2K^{+1}(aq)  + (CO_{3})^{-2}(aq)  + Mg^{+2}(aq)   + 2l^{-1}(aq)  - - > MgCO_{3} (pre) + 2K^{+1}(aq)  + 2l^{-1}(aq)  

Net ionic equation

(CO_{3})^{-2}(aq)  + Mg^{+2}(aq)  - - > MgCO_{3} (pre)  

D Na_{2}CrO_{4}(aq) + AlBr_{3}(aq)  

Ions(1) Na^{+1}  and (CrO_{4})^{-2}

Ions(2) Al^{+3} and Br^{-1}

Exchanging  

Na^{+1}  ---- Br^{-1} - ->  NaBr  

Al^{+3} ---  (CrO_{4})^{-2} - ->  Al_{2}(CrO_{4})_{3}

Products  

Na_{2}CrO_{4}(aq) + AlBr_{3}(aq) - ->  NaBr  + Al_{2}(CrO_{4})_{3}

The equation is not balanced

Balance equation is  

3Na_{2}CrO_{4}(aq) + 2AlBr_{3}(aq) - -> 6NaBr  + Al_{2}(CrO_{4})_{3}

bromides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. NaBr is soluble (aq)

chromates are always insoluble except group 1 cations. Al2(CrO4)3 is insoluble  (pre)

3Na_{2}CrO_{4}(aq) + 2AlBr_{3}(aq) - ->  6NaBr(aq) + Al_{2}(CrO_{4})_{3}(pre)

Complete ionic equation

6Na^{+1}(aq)  + 3(CrO_{4})^{-2}(aq) + 2Al^{+3}(aq) + 6Br^{-1}(aq) - -> Al_{2}(CrO_{4})_{3}(pre) +6Br^{-1}(aq) +  6Na^{+1}(aq)  

Net ionic equation

3(CrO_{4})^{-2}(aq) + 2Al^{+3}(aq) - -> Al_{2}(CrO_{4})_{3}(pre)  

You might be interested in
Wat helps measure 26 ML of a liquid
kotegsom [21]

Answer:

6 liquids

Explanation:

because yea

8 0
3 years ago
Read 2 more answers
Fluorine-18 is a positron emitter used in pet scans. write a balanced nuclear equation for the reaction.
kow [346]
<span>Due to limitations on typography, I will have to describe the equation instead of actually writing it. Crude appearance. 18 18 0 F --> O + e 9 8 1 Detailed description. Each of the 3 components have both a left superscript and a left subscript which is a superscript and a subscript to the LEFT of the main figure unlike the usual right side that you see subscripts and superscripts. The equation will be F with an 18 left superscript and a 9 left subscript to represent Florine with atomic weight of 18 and 9 protons. Followed by a right arrow to indicate the direction the reaction is going. Followed by the letter O with a left superscript of 18 and a left subscript of 8 to represent Oxygen with atomic weight of 18 and 8 protons. Followed by a plus sign to indicate more. Followed by either the lower case letter "e" or the upper case Greek character beta with a left superscript of 0 and a left subscript of 1 or +1 to represent the positron being emitted with a positive charge and an atomic weight of 0.</span>
5 0
3 years ago
Read 2 more answers
purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
stiv31 [10]

The chromium in the electrolytic solution is present as cr³⁺ will take 6.19 hours  will it take to plate 18.0 kg of chromium onto the cathode if the current passed through the cell is held constant at 45.0 A.

It is given that mass is 18 kg. Converting mass into grams

18 x (1000g / 1 kg)

= 18000 g

So, 18 kg = 18000 g

Now, calculate the number of moles

No. of moles = mass of Cr / molecular mass of Cr

No. of moles = 18000 / 52 g/mole

No. of moles = 346.15 mole

For , Cr³⁺, 3 moles of electrons are required

Hence,

3 x 346.15 mole

1038.45

As 96500 C of charge are present in 1 mole of electrons. As a result, the charge held by 1038.45 mole of electrons will be determined as follows.

= 1038.45mol x  96500 C / mole

= 10.02 x 10⁷ C

As, we know that relation between charge, current and time is as follows.

Q = I x T

Current is given as 45 A

Therefore, charge is calculated  

T = Q / I

T = 100.21 x 10⁶ / 45

T = 2.227 x 10⁶

As there are 3600 seconds in one 1 hour. Converting 2.227 x 10⁶ into hours are

= 2.227 x 10⁶ / 3600 sec/h

= 6.19 hours

Thus, if the current flowing through the cell is maintained constant at 45 A, we may estimate that it will take 6.19 hours to plate 18 kg of chromium onto the cathode.

To know more about  electrolytic solution visit :

brainly.com/question/9203208

#SPJ4

4 0
1 year ago
If a saturated solution of potassium chloride is cooled from 80℃ to 50℃,how much precipate is formed
harina [27]
Roughly 39 grams, give or take 1 gram
7 0
3 years ago
Draw the product formed when the compound shown below undergoes a reaction with hbr in ch2cl2. interactive 3d display mode
zysi [14]

Answer : The complete question is attached in the answer.


Explanation : In the given question an alkene is treated with alkylhalide in presence of methylene dichloride it gives a corresponding alkylbromide species.


The mechanism follows markonikov's addition rule, and the major product thus formed is bromine which is attached to least substituted carbon atom ad minor is bromine attached to highly substituted carbon atom.


4 0
3 years ago
Read 2 more answers
Other questions:
  • chlorine has an atomic number of 17. it often forms an ion by gaining 1 electron. what would its charge be?
    14·2 answers
  • Calculate the number of photons that would be contained in a laserpulse with a wavelength of 287 nm that contained 4.35 mJ of en
    8·1 answer
  • Which results when an atom has such a strong attraction for electrons that it pulls one or more electrons completely away from a
    13·1 answer
  • Enter your answer in the provided box. To draw a Lewis structure, first add the number of outer (valence) electrons contributed
    10·1 answer
  • Complete the equation for the dissociation of Na2CO3(aq).Omit water from the equation because it is understood to be present.
    10·1 answer
  • A vessel of 356 cm3 capacity contains oxygen at a pressure of 760 mmHg and temperature of 15 oC. Assuming that the volume remain
    9·1 answer
  • Helpppp me pleaseeee asaaap
    7·1 answer
  • The solubility of solids______ when the temperature is increased.
    9·1 answer
  • You find a 1979 copper penny (pre-1982 pennies are pure copper) in the snow and pick it up. How much heat does the penny absorb
    7·1 answer
  • Question 6 of 25
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!