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2 years ago

15

Can somebody help me with this?

2 answers:

rusak2 [61]2 years ago

5 0

Answer:

wrong

Step-by-step explanation:

(2(x + 13)) /3

the expression says x = 5, so let's check:

(2(5 + 13)) /3

36/3 = 5...FAKE

ziro4ka [17]2 years ago

4 0

Answer:

12 i don’t know.

Step-by-step explanation:

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a 12 foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece. find th

aleksandr82 [10.1K]

Use the equation
12= 3+2x

8 0

3 years ago

Use a graphing calculator to sketch the graph of the quadratic equation, and then give the coordinates for the x-

Umnica [9.8K]

Given:

The quadratic equation is

$y=6x^2-15x+6$

To find:

The x-intercepts of the given equation.

Solution:

We have,

$y=6x^2-15x+6$

Splitting the middle term, we get

$y=6x^2-12x-3x+6$

$y=6x(x-2)-3(x-2)$

$y=(x-2)(6x-3)$

For x-intercepts, y=0.

$(x-2)(6x-3)=0$

Using zero product property, we get

$x-2=0\text{ and }6x-3=0$

$x=2\text{ and }6x=3$

$x=2\text{ and }x=\dfrac{3}{6}$

$x=2\text{ and }x=0.5$

So, the x-intercepts are (0.5,0) and (2,0).

Therefore, the correct option is a.

5 0

2 years ago

In triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). F

Sophie [7]

Answer:

The length of DE is 14 cm.

Step-by-step explanation:

Given in triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). we have to find the length of DE.

Given lengths are AC=20cm, AB=17cm, and BD=11.9cm

In ΔBDE and ΔBAC

∠BDE=∠BAC (∵Corresponding angles)

∠BED=∠BCA (∵Corresponding angles)

By AA similarity rule, ΔBDE~ΔBAC

∴their corresponding sides are in proportion

⇒ $\frac{BE}{BC}=\frac{BD}{BA}=\frac{DE}{AC}$

⇒ $\frac{BD}{BA}=\frac{DE}{AC}$

⇒ $\frac{11.9}{17}=\frac{DE}{20}$

⇒ $DE=\frac{20\times 11.9}{17}=14cm$

5 0

2 years ago

Solve for x: 3(x + 1) = −2(x − 1) + 6.

Firlakuza [10]

The answer would be x=1

8 0

3 years ago

Read 2 more answers

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

2 years ago