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shepuryov [24]
3 years ago
7

(a-b)^2+2c when a=13,b=6,and c=5

Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

59

Step-by-step explanation:

Given: a = 13, b = 6, and c = 5

(13-6)^2+2 x 5 (=10)

(13-6)^2+10

=59

horsena [70]3 years ago
7 0

Answer:

59

Step-by-step explanation:

Given,

a = 13

b = 6

c = 5

To find : ( a - b )^2 + 2c

Answer : -

( a - b )^2 + 2c

= ( 13 - 6 )^2 + 2 ( 5 )

= ( 7 )^2 + 10

= 49 + 10

= 59

Therefore,

the value of ( a - b )^2 + 2c is 59.

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Step-by-step explanation:

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Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

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\mu = 200, \sigma = 50

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This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

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Step-by-step explanation:

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