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zepelin [54]
3 years ago
10

How is email a useful component of online banking? I. Email alerts can be used to warn you before you overdraw your account. II.

You can have your bank statements emailed to you, getting them to you faster. III. Only emailed bank statements can be used to support electronically-filed tax returns. A. I only b. II only c. I and II only d. I, II, and III.
SAT
1 answer:
andrey2020 [161]3 years ago
5 0

Answer:

d.

Explanation:

All 3 are examples of ways that it can help. Emails protect you from fraudulent claims also. Bank statements help with certain paperwork online like your taxes. Emailed bank statements help you with federal forums and more especially if the IRS is involved.

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Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36
AveGali [126]

Answer:

A. 2 hours walking; 12 hours running.

I am aware this is a multiple choice question. There is only one answer.

3 0
3 years ago
Read 2 more answers
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

brainly.com/question/24258023

6 0
2 years ago
considering periodic trends, valence electrons in which of the following atoms experience the greatest effective nuclear charge
Anni [7]

The <em>effective nuclear charge</em> is the difference between the atomic number an element and the shielding constant. Hence, the atom which experiences the greatest nuclear charge is Sulphur, S.

<u>Calculating the greatest effective nuclear charge</u>, :

  • Z_{eff} = Z - S

  • Z = Atomic number ; S = shielding constant

<u>For Magnesium, Mg</u>:

Z = 12

S = 10

Z_{eff} = 12 - 10 = 2

<u>For Aluminium, Al</u>:

Z = 13

S = 10

Z_{eff} = 12 - 10 = 3

For Sulphur, , S:

Z = 16

S = 10

Z_{eff} = 16 - 10 = 6

Therefore, the atom whuch experience the greatest Z_{eff} is Sulphur.

Learn more :brainly.com/question/24978746

8 0
2 years ago
C=
Blizzard [7]

Answer:

Whatever you think the answer is, go with it. Believe that you have the answer correct, and you will.

Explanation:

Believe in yourself.

3 0
3 years ago
How do you do <br><br> x√x = √216<br><br> you have to solve for x and it should equal 6
PIT_PIT [208]

Answer:

x \sqrt{x}  =  \sqrt{216}

square both sides:

{(x \sqrt{x}) }^{2}  =  {( \sqrt{216}) }^{2}

solve the roots:

( {x}^{2} .x) = 216 \\  {x}^{3}  = 216

take a cube root on both sides:

\sqrt[3]{ {x}^{3} }  =  \sqrt[3]{216}

solve the cube root:

x = 6

5 0
3 years ago
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