Question

PLEASE RESPOND.

Answer 1

Answer:

Step-by-step explanation:

Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.

Prob for drawing atleast 5 beads before she picks a grey bead from her collection

= 1-Prob for drawing atleast one grey beed in the first 5 draws.

(Because these two are complementary events)

no of grey beeds drawn in first 5 trials is

Bin$(5,\frac{80}{80+160+240} \\=(5,\frac{1}{6} )$

Prob for drawing atleast one grey beed in the first 5 draws.

=1-Prob of no grey

Hence required prob=P(X=0 in first 5 draws)

= $(1-\frac{1}{6} )^5\\=0.4018$

6th beeds onwards can be grey also.

Nearest answer is c)0.45

Answer 2

The answer could be 0.45