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3 years ago

What are radioactive isotopes?

Physics

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

Radioactive isotope , also called radioisotope,

radionuclide, or radioactive nuclide, any of

several species of the same chemical element

with different masses whose nuclei are unstable

and dissipate excess energy by spontaneously

emitting radiation in the form of alpha , beta , and

gamma rays .

A brief treatment of radioactive isotopes follows.

For full treatment, see isotope: Radioactive

Radioactiveisotopes.

Every chemical element has one or more

radioactive isotopes. For example, hydrogen, the

lightest element, has three isotopes with mass

numbers 1, 2, and 3. Only hydrogen-3 (tritium ),

however, is a radioactive isotope , the other two

being stable. More than 1,000 radioactive

isotopes of the various elements are known.

Approximately 50 of these are found in nature;

the rest are produced artificially as the direct

products of nuclear reactions or indirectly as the

radioactive descendants of these products.

Radioactive isotopes have many useful

applications. In medicine , for example, cobalt -60

is extensively employed as a radiation source to

arrest the development of cancer. Other

radioactive isotopes are used as tracers for

diagnostic purposes as well as in research on

metabolic processes. When a radioactive isotope

is added in small amounts to comparatively large

quantities of the stable element, it behaves

exactly the same as the ordinary isotope

chemically; it can, however, be traced with a

Geiger counter or other detection device.

Iodine -131 has proved effective in treating

hyperthyroidism. Another medically important

radioactive isotope is carbon-14, which is used in

a breath test to detect the ulcer-causing bacteria

Heliobacter pylori .

Explanation:

#learnwithbrainly

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A Level is set up midway between two wood hubs that are about 300 ft. apart. The rod reading on hub A is 9.09 ft. and the readin

Zarrin [17]

Answer:

The correct difference is 3.44 ft

Explanation:

The correct difference is given as

D=R_A-R_B

D=9.09-5.65

D=3.44 ft

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3 years ago

What unita are used to measure electrical current

JulijaS [17]

Answer:

It's called an ampere!

Explanation:

The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. The ampere (symbol: A) is an SI base unit Electric current is measured using a device called an ammeter.

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4 years ago

Read 2 more answers

Why does the density of a substance remain the same for different amount of the substance

tresset_1 [31]

Think of it this way:
-- Any time you have something that means (some number) PER UNIT,
it doesn't matter how many units there are on the table or in the bucket,
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-- If oranges cost $1 PER POUND, it doesn't matter how many pounds
you buy, the whole bagful is still $1 PER POUND.

-- If a certain salad dressing has 40 calories PER Tablespoon, it doesn't
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40 calories PER Tablespoon.

-- Density means '(mass) PER unit of volume'. Whether you have a tiny
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4 years ago

Suppose a horse leans against a wall as in the figure below.

Irina18 [472]

The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:

<h3>Force</h3>

Given Data

mass of horse and rider = 575kg

Force acting on wall = ??

When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object

hence the force is computed as

Force = mass * acceleration

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3 years ago

A uniform meterstick of mass 0.20 kg is pivoted at the 40 cm mark. where should one hang a mass of 0.50 kg to balance the stick?

Tcecarenko [31]

The weight of the meterstick is:
$W=mg=0.20 kg \cdot 9.81 m/s^2 = 1.97 N$
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
$d_1 = 0.50 m - 0.40 m=0.10 m$
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
$M_w = W d_1 = (1.97 N)(0.10 m)=0.20 Nm$

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
$(mg) d_2 = 0.20 Nm$
from which we find the value of d2:
$d_2 = \frac{0.20 Nm}{mg}= \frac{0.20 Nm}{(0.5 kg)(9.81 m/s^2)}=0.04 m$

So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.

4 0

4 years ago