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disa [49]
3 years ago
11

What are radioactive isotopes?

Physics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

<em><u>R</u></em><em><u>adioactive isotope</u></em> , also called radioisotope,

radionuclide, or radioactive nuclide, any of

several species of the same chemical element

with different masses whose nuclei are unstable

and dissipate excess energy by spontaneously

emitting radiation in the form of alpha , beta , and

gamma rays .

A brief treatment of radioactive isotopes follows.

For full treatment, see isotope: <u>Radioactive</u>

<u>Radioactiveisotopes.</u>

Every chemical element has one or more

radioactive isotopes. For example, hydrogen, the

lightest element, has three isotopes with mass

numbers 1, 2, and 3. Only hydrogen-3 (tritium ),

however, is a radioactive isotope , the other two

being stable. More than 1,000 radioactive

isotopes of the various elements are known.

Approximately 50 of these are found in nature;

the rest are produced artificially as the direct

products of nuclear reactions or indirectly as the

radioactive descendants of these products.

Radioactive isotopes have many useful

applications. In medicine , for example, cobalt -60

is extensively employed as a radiation source to

arrest the development of cancer. Other

radioactive isotopes are used as tracers for

diagnostic purposes as well as in research on

metabolic processes. When a radioactive isotope

is added in small amounts to comparatively large

quantities of the stable element, it behaves

exactly the same as the ordinary isotope

chemically; it can, however, be traced with a

Geiger counter or other detection device.

Iodine -131 has proved effective in treating

hyperthyroidism. Another medically important

radioactive isotope is carbon-14, which is used in

a breath test to detect the ulcer-causing bacteria

Heliobacter pylori .

Explanation:

#learnwithbrainly

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If a hot air balloon is seen rising above the top of a hill, what is the top of the hill called? Question 2 options: delta point
timofeeve [1]

If a hot air balloon has shown rising above the top of a hill, the top of the hill is considered as a reference point.

<h2>Reference Point:</h2>

It is a point that is used to standardize a experiment. The reference point is a constant point.

In the given problem:

  • The hot air balloon is rising above the top of the hill. Here, the hill is a standard point that has a fixed (constant) height.
  • Some other reference points are the top of the Eifel Tower or a famous shop which a person use to denote a certain distance.

Therefore, "If a hot air balloon has shown rising above the top of a hill" the top of the hill is considered as a reference point.

Learn more about Reference Point:

brainly.com/question/1674904

5 0
2 years ago
A fox runs at a speed of 16 m/s and then stops to eat a rabbit. If this all took 120
GalinKa [24]

Answer:

a = 52s²

Explanation:

<u>How to find acceleration</u>

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

<u>Solve</u>

We know initial velocity (u = 16), velocity (v = 120) and acceleration (a = ?)

We first need to solve the velocity equation for time (t):

v = u + at

v - u = at

(v - u)/a = t

Plugging in the known values we get,

t = (v - u)/a

t = (16 m/s - 120 m/s) -2/s2

t = -104 m/s / -2 m/s2

t = 52 s

7 0
3 years ago
what happens to the period of revolution for the planets as they move farther away in position from the sun
Marina CMI [18]
It increases. Mercury takes 88 days to orbit the sun once. The Earth takes a year. Pluto takes 248 years.
3 0
4 years ago
A fire helicopter carries a 700-kg bucket of water at the end of a 20.0-m long cable. Flying back from a fire at a constant spee
rodikova [14]

Answer:

F = 50636.873 N

Explanation:

given,

bucket of water =  700-kg

length of cable = 20 m

Speed  = 40 m/s

angle of the cable = 38.0°

let air resistance be = F

tension in rope be = T

T cos 38° = m×g..................(1)

T sin 38^0= \dfrac{mv^2}{l} + F..........(2)

equation (1)/(2)

tan 38^0 =\dfrac{\dfrac{mv^2}{l} + F}{mg}

       0.781=\dfrac{\dfrac{700\times 40^2}{20} + F}{700\times 9.8}

           F = 50636.873 N

Hence the force exerted on the bucket is equal to F = 50636.873 N

5 0
3 years ago
I need help with this
lisabon 2012 [21]
A. Condensation

Hope this helps!!!
5 0
2 years ago
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