Explanation:
It is given that,
Weight of the rock in air, W = 110 N
Since, W = mg
m = 11.22 kg
We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.
d is the density of water,
V is the volume of rock,
M = 3.37 kg
The apparent weight in water, W = m - M
W = 76.93 N
So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.
Answer: 7.5 rev/s
Explanation:
We are given the angular velocity a helicopter's main rotor blades:
However, we are asked to express this in the International Systrm (SI) units. In this sense, the SI unit for time is second (
):
Answer:
Explanation:
<u>Elastic Potential Energy </u>
Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.
Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.
Solving for Δx:
Substituting:
Calculating: