All categories

3 years ago

Write f(2)=3 in coordinate form (x,y)

Mathematics

1 answer:

-BARSIC- [3]3 years ago

5 0

Answer:

Coordinate form is $(x,y)=(2,3)$

Step-by-step explanation:

Usually the form is

$f(x)=y$

Here

We have $f(2)=3$

Hence $(x,y)=(2,3)$

You might be interested in

Given The following Graph: a.)Evaluate f(0). b.) Solve for f(x) = -3

dlinn [17]

Answer:

see explanation

Step-by-step explanation:

f(0) means find the value of y when x = 0

That is f(0) = 1 ← the point (0, 1) on the graph

When f(x) = - 3 means what are the values of x corresponding to y = - 3

From the graph when y = - 3 there are 2 corresponding values of x, that is

x = - 2 or x = + 2

The solution to f(x) = - 3 is x = ± 2

3 0

4 years ago

Evaluating integral by net area

N76 [4]

The graph of $f(x)=2$ is a horizontal line. So the area under $f(x)$ on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of $g(x)=\sqrt{64-x^2}$ is the upper half of a circle with radius $\sqrt{64}=8$ . It's symmetric about $x=0$ , so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is $\frac{\pi 8^2}4=16\pi$ .

Then use the fact that the definite integral is distributive over sums, meaning

$\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi$

8 0

3 years ago

11) Endpoint: (0,4), midpoint (-10, -3) Find the endpoint?

earnstyle [38]

Answer:

(-20,-10)

Step-by-step explanation:

$( - 10 \: \: - 3) = ( \frac{0 + x}{2} \: \: \frac{4 + y}{2} )$

Solve for.x coordinate

$- 10 = \frac{0 + x}{2} \\ - 20 = 0 + x \\ x = - 20$

solve for y coordinate

$- 3 = \frac{4 + y}{2} \\ - 6 = 4 + y \\ - 10 = y$

5 0

4 years ago

In 10 words or fewer, define rectangle.

oee [108]

Answer:

a figure with four straight sides and four right angles.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

X^2+2x+9=0 please?!

Nadusha1986 [10]

Answer:

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

We can solve for x using the quadratic formula

x² + 2x + 9 = 0 ← is in standard form

with a = 1, b = 2 and c = 9

x = ( - 2 ± $\sqrt{2^2-(4(1)(9)}$ ) / 2

= ( - 2 ± $\sqrt{4-36}$ ) / 2

= (- 2± $\sqrt{-32}$ ) / 2)

= (- 2 ± $\sqrt{16(2)(-1)}$ ) / 2

= ( - 2 ± 4i $\sqrt{2}$ ) / 2

= $\frac{-2}{2}$ ± $\frac{4i\sqrt{2} }{2}$

= - 1 ± 2i $\sqrt{2}$ → D

5 0

3 years ago

Read 2 more answers