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erastova [34]
3 years ago
5

Ebgjwbjhkjfhdsn wmiuehdbnsmkji

Mathematics
2 answers:
posledela3 years ago
5 0

DYK?

— Pretty face is everywhere, but a woman who cheer you up at your weakest and stay after knowing about your flaws and bad sides are rare, so you better keep her dude!.

#moodchallenge

natali 33 [55]3 years ago
4 0

Answer:

im srry what

Step-by-step explanation:

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Which value satisfies the inequality -2x + 8 + 5x > 2x + 1? A) -15 B) -10 C) -7 D) -5
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<span>-2x + 8 + 5x > 2x + 1
3x + 8 > 2x + 1
         x > -7

answer
D) - 5</span>
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29
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Answer:

69 need to be added

Step-by-step explanation:

1300 +69 = 1369

37 ²  = 1,369

square root of 1,369 is 37

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Write an expression that is equivalent to (4x + 9)
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As this is already in its simplest form, I believe the only other expression is 4*X +9
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Can the sides of a triangle have lengths 1, 4, and 7?
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In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p
hichkok12 [17]

Answer:

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

4 0
3 years ago
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