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3 years ago

Write the equation it passes through (-5,-7) and (-5,7)

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

Answer:

x = -5

Step-by-step explanation:

Find the gradient:

m = change in y ÷ change in x
m = (7 - -7) ÷ (-5 - -5)
m = 14 ÷ 0
m = 0 - There is no gradient, and it is a vertical line

The equation is x = -5, because in both co-ordinate pairs, the x is -5 - only the y changes

Hope this helps!

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15m+m+2 <br> I need help on combining like terms

Mice21 [21]

Answer:

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Step-by-step explanation:

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3 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

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Answer:

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