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balandron [24]
3 years ago
9

In a vacuum light travels at which speed?

Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

Light traveling through a vacuum moves at exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second

Explanation:

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What kind of circuit
MatroZZZ [7]

Answer:

parallel circuit

Explanation:

voltage will be same for both light bulbs and current will be different.

6 0
3 years ago
A single circular current loop 14.0 cm in diameter carries a 2.40 A current. You may want to review . For related problemsolving
7nadin3 [17]

Answer:

Magnetic field at the center will be 215.314\times 10^{-7}T

Explanation:

We have given that diameter of the loop d = 14 cm = 0.14 m

So radius R=\frac{d}{2}=\frac{0.14}{2}=0.07m

Current in the loop i = 2.40

We know that magnetic field at center of circular loop is given by

B=\frac{\mu _0i}{2R}

So B=\frac{4\pi \times 10^{-7}\times 2.4}{2\times 0.07}=215.314\times 10^{-7}T

Magnetic field at the center will be 215.314\times 10^{-7}T

8 0
3 years ago
Which type of information about rattlesnakes does the bar graph above show?
Andrei [34K]

Answer:

Variation

Explanation:

5 0
3 years ago
Who came up with the theory of relativity?
liberstina [14]

Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels

5 0
4 years ago
An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if
N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]  

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.  

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.  

I hope this helps!

Explanation:

8 0
3 years ago
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