1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum
Complete question:
use the hubble's law to determine the distance to a quasar receding at 75% the speed of light. The speed of light is 300,000 km/sec. assume Hubble's constant is 2.2 x 10⁻⁵ km/s/Lyr
Answer:
The distance to the quasar is 1.02 x 10¹⁰ Lyr
Explanation:
Given;
speed of light, v = 300, 000 km/sec
Hubble's constant, H₀ = 2.2 x 10⁻⁵ km/s/Lyr
percentage of the quasar recession = 75% of speed of light
Hubble's Law is given by;
Therefore, the distance to the quasar is 1.02 x 10¹⁰ Lyr
Answer:
Gravitational potential energy to kinetic energy
Explanation:
In this case you have a case about conservation of energy.
When the mass is released and allowed to fall, its energy is completely gravitational potential energy with a value of U = mgh. m is the mass, g is the gravitational constant and h is the height to the floor from the mass.
While the mass is falling down part of its potential energy converts to kinetic energy of value K=1/2mv^2, because the mass has been acquiring more and more velocity.
Thus, the kinetic energy is increasing while the potential energy is decreasing.
When the mass is just above the floor (the moment just before the mass hits the floor) all its potential energy has been converted to kinetic energy.
Then, you have that the kinetic energy of the mass when the mass is just above the floor, is equal to the potential energy when the mass is at height of h. That is:
This is how the law of conservation of energy is fulfilled.
Answer:
Secant line is a straight line which joins the two points of functions and it also represents the slope between two points.
Explanation:
Secant line is also known as average rate of change of functions between two points and also called slope.
In mathematical form,
Secant line = average rate of change = slope
Slope m = y/x