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2 years ago

Please help it will be brainlist as long as it’s right

Mathematics

2 answers:

tatuchka [14]2 years ago

7 0

Answer:

It should be 20

Step-by-step explanation:

rjkz [21]2 years ago

4 0

Answer:

Step-by-step explanation:

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Determine whether the random variable is discrete or continuous. In each case, state the possible values of the random variable

yan [13]

Answer:

a) C. The random variable is discrete. The possible values are xequals0, 1, 2,....

b) B. The random variable is continuous. The possible values are x greater than or equals 0.

Step-by-step explanation:

Discrete variables are countable in a finite amount of time. Continuous variables can be infinitely many. They rather assume values in a range.

(a) Is the number of hits to a Web site in a day discrete or continuous?

C. The random variable is discrete. The possible values are x equals 0, 1, 2,....

(b) Is the weight of a Upper T dash bone steak discrete or continuous?

B. The random variable is continuous. The possible values are x greater than or equals 0.

8 0

2 years ago

Find each equation with the correct solution

stepladder [879]

Answer:

15;9;-8

Step-by-step explanation:

1. 5/3x-3=2/3x+12

x=15 once you combine like terms

2. 5x+35-3x+12=7x+2

2x+47=7x+2

5x=45

x=9

3. 12x+20-3=9x-7

12x+17=9x-7

3x=-24

x=-8

3 0

2 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$