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Alex_Xolod [135]
3 years ago
10

Line v has an equation of y=–109x–3. Perpendicular to line v is line w, which passes through the point (2,3). What is the equati

on of line w?
Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

the equation of line w will be y = 1/109x + 325/109

Step-by-step explanation:

when a line is perpendicular to another line, that means their slopes are reversed signs and flipped.

so if one slope is 2/3, the perpendicular slope would be -3/2

so in this problem, line w would have 1/109 be the slope.

using this, we can substitute m as the slope and the given point in the problem as x and y and solve for b in the slope-intercept form (y = mx +b)

m = 1/109

(2,3)

y = mx + b

3 = (1/109)2 + b

3 = 2/109 + b

327/109 = 2/109 + b

325/109 = b

putting it all together, the equation of line w will be y = 1/109x + 325/109

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