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2 years ago

HELPPP what is the value of 6n-2 when n=3? I BEG

2 answers:

5 0

1st you would need to multiply 6 and 3 since n=3 which would give you 18. Then simply subtract 2 which would give you 16

The final answer is 16.

ivann1987 [24]2 years ago

3 0

Answer:

Step-by-step explanation:

If $n = 3$ , just put the number $3$ instead of $n$ .

So:

$6n-2 = 6 * 3 - 2 = 18 - 2 = 16$

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Simplify: (ab + bc) (ab - bc)

yanalaym [24]

$\: \: \: \:$

$= {a}^{2} \: {b}^{2} - {b}^{2} \: {c}^{2}$

Step-by-step explanation:

$(ab + bc)(ab - bc)$

use ( a + b ) ( a + b ) = a² - b² to simply the product

$(ab {)}^{2} - (bc {)}^{2}$

to raise a product to a power ,raise each factor to that power

$= {a}^{2} {b}^{2} - {b}^{2} {c}^{2}$

<h2>hope it helps</h2>

6 0

1 year ago

What is greater 5.7 or5.18 ?what is the answer?

arsen [322]

5.7 is greater than 5.18.

4 0

2 years ago

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What is the complete factorization of the polynomial below x^3-2x^2+x-2

stiv31 [10]

Answer:

$(x^2+1)(x-2)$

Step-by-step explanation:

The polynomial given is: $x^{3}-2x^{2}+x-2$

Grouping the first 2 terms together and the last 2 terms together and taking common, we have:

$x^3-2x^2+x-2\\=(x^3-2x^2)+(+x-2)\\=x^2(x-2)+1(x-2)\\=(x^2+1)(x-2)$

This is the complete factorization.

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2 years ago

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Consider the following set of equations:

ivanzaharov [21]

No solution because both equations have 2x on the same side.

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2 years ago

I would really appreciate it if you could help me solve this thing. Thanks!

Montano1993 [528]

I believe LKJI is congruent to NKJM.

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2 years ago