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Naddika [18.5K]
3 years ago
7

Two fair dice, one yellow and one blue, are rolled. The value of the blue die is subtracted from the value of the yellow die. Wh

ich of the following best describes the theoretical probability distribution?
A) constant
B) symmetric
C) positively skewed
D) negatively skewed
Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0

Answer:

its B symmetric

Step-by-step explanation:

got it right on ed

mario62 [17]3 years ago
4 0

Answer:

B) symmetric

Step-by-step explanation:

We will find the sample space for rolling two dices first

Here first value in ordered pair represents yellow die and second represents blue die

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

The subtraction gives us:

0 , -1 , -2, -3, -4, -5, 1, 0, -1, -2, -3, -4, 2, 1, 0, -1, -2, -3, 3, 2, 1, 0, -1, -2, 4, 3, 2, 1, 0, -2, 5, 4, 3, 2, 1, 0

So the distribution will be as follows:

X      5       4       3       2        1        0        -1       -2      -3       -4      -5

P(X)  1/36  2/36  3/36 4/36  5/36  6/36  5/36  4/36  3/36  2/36  1/36

By observing the probabilities, we can conclude that the distribution will be symmetric

Hence, Option B is correct ..

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The equation is false so no solution.

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Step-by-step explanation:

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Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
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Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

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