“Equally likely outcomes in probability.
In some sample spaces, it is reasonable to estimate or assume that all outcomes in the space are equally likely (that they occur with equal probability). For example, when tossing an ordinary coin, one typically assumes that the outcomes "head" and "tail" are equally likely to occur.”
Answer: 80
Step-by-step explanation: pls mark my answer as brainlist
Answer:
x
=
3
+
15y/
2
x
=
−
1
+
6
y
Step-by-step explanation:
your welcome
4, 4, 6, 7, 9, 9, 9, 10, 14, 17, 21 <br>
Mean:<br><br>
Median:<br><br>
Mode:<br><br>
Range:
Anastasy [175]
Answer:
Mean: 10
Median: 9
Mode: 9
Range: 17
Step-by-step explanation:
Mean is adding all the numbers together then *divide by the number of numbers you added:
4 + 4 + 6 + 7 + 9 + 9 + 9 + 10 + 14 + 17 + 21 = 110
110 / 11 = 10
Median is the middle number: 9
The number that appears the most often is the mode: 9
The range is the difference between the lowest and highest number:
21 - 4 = 17
12 - 24 = -12
810 - 23 = 787
23 - 14 = 9
