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Vikki [24]
2 years ago
12

Please help me, It's due soon! Giving brainliest too!

Mathematics
1 answer:
ANEK [815]2 years ago
7 0

Answer:

gimme a sec

Step-by-step explanation:

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What is the LCD of 1/4a and 5/6a
inessss [21]
1/(4a) & 5/(6a)
(3)(1/4a)=3/12a
(2)(5/6a)=10/12a
LCD=12a
7 0
3 years ago
If -6x + 12 = 0 and 4y + 5 =9 <br> what is the value of x + y
slega [8]

Answer:

x=2

y=1

Step-by-step explanation:

-6x+12=0

take 12 to the other side &it becomes negated then equate

-6x=-12

the negatives cancel out each other and therefore the answer is positive

x=2

4y+5=9

take 5 over to the other side &it becomes negated

4y=9-5

4y=4

y=1

8 0
3 years ago
Read 2 more answers
Dorothy Little purchased a mailing list of 2,000 names and addresses for her mail order business, but after scanning the list sh
andrew-mc [135]

Answer:

P(X > 0) = 0.9222

Step-by-step explanation:

For each name, there are only two outcomes. Either the name is authentic, or it is not. So, we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem.

5 names are selected, so n = 5

A success is a name being non-authentic. 40% of the names are non-authentic, so \pi = 0.40.

We have to find P(X > 0)

Either the number of non-authentic names is 0, or is greater than 0. The sum of these probabilities is decimal 1. So:

P(X = 0) + P(X > 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{5,0}*(0.40)^{0}*(0.6)^{5} = 0.0778

So

P(X > 0) = 1 - P(X = 0) = 1-0.0778 = 0.9222

5 0
3 years ago
Can u guys PLEASE answer this question ASAP.
TEA [102]

Calculate Paul's bonus.

$66 000 : 12 = $5 500

4 0
3 years ago
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Use this chart to estimate the fractional part of the orchard that is
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