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adell [148]
3 years ago
9

The measures of the angles in a triangle have a ratio of 2:9:1. How do you find the measures of these angles

Mathematics
1 answer:
romanna [79]3 years ago
8 0
Hello. Firstly you have to remembet that the sum of the three angles in any triangle is 180grades
So, determining the constant (k) you will have:
2:9:1
2k+9k+1k=180
12k=180 180/12=k
k = 15
Multiply the constant by 180 and divide by the given ratio:
180*15 / 2
180*15 / 9 etc
then your angles are
2:9:1
24:108:12

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Easiest way:

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A slope of 4 would mean that 1 step to the right is followed by 4 steps upwards. A slope of -5 means 1 step to the right, 5 steps downwards.

To get from A to E you need 9 steps to the right and 3 steps upwards. This means a 3/9 slope. The simplest form of it is 1/3. 
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I hope this was understandable, this is how they taught me this in 5th grade more than a decade ago. 
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<em>Y</em>₁ and <em>Y</em>₂ are independent, so their joint density is

f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}

By definition of conditional probability,

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = P((<em>Y</em>₁ > <em>Y</em>₂) and (<em>Y</em>₁ < 2 <em>Y</em>₂)) / P(<em>Y</em>₁ < 2 <em>Y</em>₂)

Use the joint density to compute the component probabilities:

• numerator:

P((Y_1>Y_2)\text{ and }(Y_1

=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1

=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty

=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16

• denominator:

P(Y_1

(I leave the details of the second integral to you)

Then you should end up with

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = (1/6) / (2/3) = 1/4

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2 years ago
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