Ax^2+bx+c=0
a=leading term
ok so if the leading term is positive then opens up and has a min
if leading term is negative then opens down and has a max
leading term is positive
1x^2+8x
has a max
to complete the square, move c aside take 1/2 of b and square it
b=8
8/2=4
4^2=16
now add that to both sides
x^2+8x+16+6=0+16
factor perfect square
(x+4)^2+6=16
subtract 6
(x+4)^2=10
subtract 10
(x+4)^2-10=0
vertex aka min or max is (h,k) when ou have
y=a(x-h)+k
h=-4
k=-10
C
Answer:
<u><em>A & B</em></u>
Step-by-step explanation:
..
Y - y1 = m(x - x1)
slope(m) = -2
(3,1)....x1 = 3 and y1 = 1
now we just sub
y - 1 = -2(x - 3) <== point slope form
<span>Am nevoie de mai multe informații pentru a răspunde la întrebarea dvs.
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1. 2880
2. 67%
Its simple math just put in effort
