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Bad White [126]
3 years ago
9

Simply. the answer should only contain positve exponets.

Mathematics
1 answer:
Murljashka [212]3 years ago
5 0
That's really an ugly mess.  I'm sure it can be greatly simplified.

                               2 m²  p⁻¹  q⁴  /  m⁴ p⁻¹ q⁴ m² q⁻³

-- There's  m²  on top and also  m²  on the bottom.  They can be cancelled.
-- There's  p⁻¹  on top and also  p⁻¹  on the bottom.  They can be cancelled.
-- There's  q⁴  on top and also  q⁴  on the bottom.  They can be cancelled.

So here's what we have left now:

                                         <span>2              /  m⁴           q⁻³

That's IT !  After only some cancelling.


We can take the  q⁻³  out of the denominator,</span>
and make it  q³  in the numerator.  
And here's what we have now:  

                                       <span>2  q³  /  m⁴   .

And I think that's really the end.
It looks much better now.
</span>
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Is the DIAMETER of a circle proportional to its circumference???
Elodia [21]

Answer:

Is the DIAMETER of a circle proportional to its circumference??

1. One of the unique qualities of a circle is that its diameter and circumference have a proportional relationship.

2. This means that no matter what size the circle is, the proportional relationship, or ratio, between its circumference and diameter is always the same.

Is the RADIUS of a circle proportional to its area??

1. Yes, the circumference of a circle is proportional to its radius.

2. Double the radius and you double the circumference.

3 0
3 years ago
Solve r = 1/2m^2p for p
hoa [83]
You just have to arrange the equation such that the p is the only term at the left hand side of the equation. Express it in terms of r and m. 

r = 1/2*m²*p
Divide both left and right hand side equations by 1/2*m²
p = r/(1/2 *m²)
Take the reciprocal of 1/2 and multiply it. The final answer is:
p = 2r/m²
7 0
3 years ago
A baker is building a rectangular solid box from cardboard to be able to safely deliver a birthday cake. The baker wants the vol
k0ka [10]

The length of the rectangular delivery box must be equal to 4 inches.

Let the length of the box be L.

Let the width of the box be W.

Let the height of the box be H.

<u>Given the following data:</u>

  • Volume of box = 224 cubic inches.

Translating the word problem into an algebraic expression;

W = 3 + L  ......equation 1

H = 4 + L  ......equation 2.

Mathematically, the volume of a rectangular solid is given by the formula;

Volume = length * width * height  .....equation 3.

Substituting the values into equation, we have;

224 = L * (3 + L) * (4 + L)\\\\224 = (3L + L^{2})* (4 + L)\\\\224 = 12L + 3L^{2} + 4L^{2} + L^{3} \\\\224 = 12L + 7L^{2} + L^{3}

Rearranging the polynomial, we have;

L^{3} + 7L^{2} +  12L - 224 = 0

We would apply the remainder theorem to solve the polynomial.

According to the remainder theorem, if a polynomial P(x) is divided by (x - r) and there is a remainder R; then P(r) = R.

When x = 3

(x - 3) = 0\\x = 3

P(3) = 3^{3} + 7(3^{2}) + 12(3) - 224\\\\P(3) = 27 + 7(9)  + 36 - 224\\\\P(3) = 27 + 63 + 36 - 224 = -98 \neq 0

We would try with 4;

P(4) = 4^{3} + 7(4^{2}) + 12(4) - 224\\\\P(4) = 64 + 7(16)  + 48 - 224\\\\P(4) = 64 + 112 + 48 - 224\\\\P(4) = 224  - 224 = 0

Therefore, 4 is one of its roots.

Hence, the length of the rectangular delivery box must be equal to 4 inches.

Find more information on polynomial here: brainly.com/question/10689855

3 0
3 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
Which chocolate chip cookies have the greater spread in the number of chips per cookie?
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Reduced fat had the greater spread
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