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max2010maxim [7]
3 years ago
12

The figure below is a square pyramid. What is the surface area of the figure?

Mathematics
2 answers:
Anna [14]3 years ago
5 0

Answer:

surface area of the square pyramid

(6×6)+(2×6×5)

36+60

96 square meters

answer is option 4

CaHeK987 [17]3 years ago
4 0

Answer:

120

Step-by-step explanation:

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Find the cartesian product Ax B of the following sets a) A = {x:x=1,2,3},b{y:y=3-x}​
BabaBlast [244]

Answer:

Step-by-step explanation:

A=(1,2,3)

B=(0,1,2)

A×B=(1,2,3)×(0,1,2)

A×B=((0,1),(1,1),(1,2),(0,2),(1,2),(2,2),(0,3),(1,3),(2,3))

3 0
2 years ago
Can someone please help:(<br> 20 points??
77julia77 [94]

the answer might me B, not enough information to determine. if not that then D

3 0
4 years ago
PLEASE ANSWER THIS ASAP, I WILL BE GIVING YOU A THANKS! .
timama [110]

Answer:

D.) 12

Step-by-step explanation:

16x - 3(4x + 5) = 2x + 9

16x - 12x - 15 = 2x + 9

4x - 2x = 15 + 9

2x = 24

2x/2 = 24/2

x = 12

Check:

16x - 3(4x + 5) = 2x + 9

16(12) - 3(4(12) + 5) = 2(12) + 9

192 - 3(48 + 5) = 2(12) + 9

192 - 3(53) = 24 + 9

192 - 159 = 33

33 = 33

3 0
3 years ago
A jogger goes half a mile north and then turns west. If the jogger finishes 1.3 miles away from the starting point, how far west
Ratling [72]
In order to solve this problem, you must draw a right triangle first to help you visualize the path of the jogger. 
You are given 0.5 miles north (which will be the height of the right triangle), and 1.3 miles (which will be the hypotenuse of the triangle). 
Using Pythagorean Theorem: a²+b²=c², we have:
0.5² + b² = 1.3²
b = 1.3²-0.5²
b = 1.2 miles
3 0
3 years ago
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

16 = PM

PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

15 = PM

PM = 15 cm

3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

7 0
3 years ago
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