Answer:
V H2O = 170.270 mL
Explanation:
- QH2O ( heat gained) = Qcoffe ( heat ceded)
⇒ Q = m<em>C</em>ΔT
∴ m: mass (g)
∴ <em>C</em>:<em> </em>specific heat
assuming:
- δ H2O = δ Coffe = 1.00 g/mL
- <em>C</em> H2O = <em>C</em> coffe = 4.186 J/°C.g....from literature
⇒ Q coffe = (mcoffe)(C coffe)(60 - 95)
∴ m coffe = (180mL)(1.00 g/mL) = 180 g coffe
⇒ Q = (180g)(4.186 J/°C.g)(-35°C) = - 26371.8 J
⇒ Q H2O = 26371.8 J = (m)(4.186 J/°C.g)(60 - 23)
⇒ (26371.8 J)/(154.882 J/g) = m H2O
⇒ m H2O = 170.270 g
⇒ V H2O = (170.270 g)(mL/1.00g) = 170.270 mL
I pretty sure that it’s b
Sedimentary rocks form layers.
Answer:

ΔG ≅ 199.91 kJ
Explanation:
Consider the reaction:

temperature = 298.15K
pressure = 22.20 mmHg
From, The standard Thermodynamic Tables; the following data were obtained






The equilibrium constant determined from the partial pressure denoted as
can be expressed as :


= 0.045

where;
R = gas constant = 8.314 × 10⁻³ kJ



199.912952 kJ
ΔG ≅ 199.91 kJ