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Greeley [361]
3 years ago
6

PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!!

Chemistry
2 answers:
erastova [34]3 years ago
4 0

Answer:

HELP ASAP!! Evaluate the extent to which the United States government and people have reconciled social, economic, and political disparities with regards to the nation’s founding principles.

marin [14]3 years ago
3 0
A. V = 11 x 7 x 10
= 770 cm3
b. D = 825g/ 770cm3
= 1.07 gcm-3

Hope this helps!
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Consider the decomposition of hydrogen peroxide reaction. If the rate of decomposition of hydrogen peroxide at a particular temp
Natasha2012 [34]

Answer:

0.049 mol/L.s

Explanation:

The decomposition of hydrogen peroxide is:

H_2O_2 \to H_2O + \dfrac{1}{2}O_2

Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2  \Delta [H_2O_2]}{\Delta t}

The rate of decomposition reaction = the rate of formation of H_2O = 0.098 mol/L.s

∴

Rate of formation of O_2 = \dfrac{ rate \ of \ reaction }{2}

= \dfrac{ 0.098 }{2}

= 0.049 mol/L.s

8 0
3 years ago
Please help me with this thank you I’ll give extra credit! Thank you againnnn !!
Anon25 [30]

Answer: i have not 1 idea

Explanation:

4 0
3 years ago
Calculate the following quantity: volume of 1.403 M copper(II) nitrate that must be diluted with water to prepare 575.2 mL of a
Juliette [100K]

Answer:

328 ml

Explanation:

We have given final volume =575.2 ml=0.575 L

Final concentration = 0.8012 M

We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles

We have to find initial volume

So initial volume =\frac{moles\ of \ copper(II)\ nitrate}{initial\ concentration}=\frac{0.4606}{1.403}=0.328L=328ml

6 0
4 years ago
Will give brainlist need answers asap
lord [1]

Answer:

2nd and 4th ones

Explanation:

More sugar dissolves in water than salt

  more aspirin dissolves in water than CO2 ...but less aspirin than table salt (NaCl)

5 0
2 years ago
A compound is a substance composed of two or more elements that are
Anastaziya [24]
Chemically bonded together
3 0
4 years ago
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