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mixas84 [53]
3 years ago
13

Why chemically did the prescribing of thalidomide for morning sickness in pregnant women lead to tragic consequences, including

teratogenic effects?
Chemistry
1 answer:
Dominik [7]3 years ago
3 0

Answer:

See explanation

Explanation:

The drug thalidomide with molecular formula C13H10N2O4 was widely prescribed by doctors for morning sickness in pregnant women in the 1960s.

The drug was sold as a racemic mixture  (+)(R)-thalidomide and (-)(S)-thalidomide.

Unfortunately, only the  (+)(R)-thalidomide exhibited the required effect while (-)(S)-thalidomide is a teratogen.

This goes a long way to underscore the importance of separation of enantiomers in drug production.

Therefore, all the teratogenic effects observed when using the drug thalidomide was actually as a result of the presence of (-)(S)-thalidomide, the unwanted enantiomer.

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A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo
Liula [17]

<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0
3 years ago
Help plsssssss... 3C(s) + 2Fe2O3 (5) ► Fe
blondinia [14]

Answer:

single displacement

Explanation:

the Fe was switched out with the C. they are the only ones that switched, making it a single displacement

6 0
3 years ago
Read 2 more answers
Can an ether form hydrogen bonds in the same way as does an ester
belka [17]

Yes, an OH group from ethanol can form a hydrogen bond to the ether O atom in the same way as it can do so with the single-bonded O atom in the ester.

The O atom in the carbonyl group of the ester can also form H-bonds with ethanol.


5 0
3 years ago
How many moles is 3.85 x 1025 atoms of gold?
stich3 [128]

Answer:

3.45 x 10^24 x 1 / 6.022 x 10^23 = 573 

4 0
2 years ago
Draw the Lewis structure for BCl3. How many single bonds, double bonds, triple bonds, and unshared pairs of electrons are on the
andreev551 [17]

Answer :  The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, BCl_3

As we know that boron has '3' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in BCl_3 = 3 + 3(7) = 24

According to Lewis-dot structure, there are 6 number of bonding electrons and 18 number of non-bonding electrons.

From the Lewis-dot structure we conclude that,

The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

3 0
3 years ago
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