Solid magnesium has mass of 1300g and a volume of 743cm . what's the density of magnesium?

In the single displacement reaction of HCl and magnesium, how many grams of magnesium chloride would be produced if 1.05g of mag

iren [92.7K]

Answer:

4.16g of MgCl2

Explanation:

First, let us generate a balanced equation for the reaction:

Mg + 2HCl —> MgCl2 + H2

Molar Mass of Mg = 24g/mol

Molar Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g

From the equation,

24g of Mg produced 95g of MgCl2.

Therefore, 1.05g of Mg will produce = (1.05x95)/24 = 4.16g of MgCl2

5 0

3 years ago

Can someone please help me with this question

12345 [234]

Explanation:

a) 3Pb(NO3)2 + Al2(SO4)3 ---> 3PbSO4 + 2Al(NO3)3

Double displacement

b) 2Cl2 + 3O2 ---> 2Cl2O3

Synthesis

c) 2Fe2O3 + 3C ---> 4Fe + 3CO2

single displacement

8 0

3 years ago

If a 7.0 mL sample of vinegar was titrated to the stoichiometric equivalence point with 7.5 mL of 1.5M NaOH, what is the mass pe

NNADVOKAT [17]

First we need to calculate the number of moles of NaOH titrated.

molar concentration = number of moles / solution volume (liter)

number of moles = molar concentration × solution volume

number of moles of NaOH = 1.5 × 0.0075 = 0.01125 moles

Then we look at the chemical reaction:

CH $_{3}$ -COOH + NaOH = CH $_{3}$ COONa + H $_{2}$ O

We can see that 1 mole of acetic acid is reacting with one mole of sodium hydroxide. Then we can conclude that 0.01125 moles of sodium hydroxide reacts with 0.01125 moles of acetic acid.

Now we can get the mass of acetic acid:

number of moles = mass (grams) / molecular mass (g/mol)

mass = number of moles × molecular mass

mass of acetic acid = 0,01125 × 60 = 0.675 g

We assume that the density of the vinegar = 1 g/mL, so the mass percent of acetic acid is:

concentration of acetic acid = (mass of acetic acid / mass of vinegar) × 100

concentration of acetic acid = (0.674 / 7) × 100 = 9.6 %

3 0

3 years ago

A certain radioactive isotope placed near a Geiger counter registers 160 counts per second. 32 hours later, the counter register

stealth61 [152]

I believe that the answer for this question would be option A. 8 HOURS. Based on the given scenario above about a certain radioactive isotope placed near a Geiger counter, the half-life <span>of the isotope 32 hours later would be 8 hours. Hope this is the answer that you are looking for. </span>

7 0

3 years ago

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A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorime

Keith_Richards [23]

Answer: $4.994\times 10^{-3}$ moles

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass , occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given mass of ethanol = 0.2301

Molar mass of ethanol = 46.07 g/mol

$\text{Number of moles of ethanol}=\frac{0.2301g}{46.07g/mol}=4.994\times 10^{-3}$

Thus there are $4.994\times 10^{-3}$ moles of ethanol are present in the sample.

7 0

3 years ago

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