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algol13
3 years ago
10

USE YOUR OWN WORDS. Each question must have a three sentence long answer!

Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

You're weird

Explanation:

Just saying

ivolga24 [154]3 years ago
3 0

Answer:

I don't know zkjfn

Explanation:

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If you are traveling at 60mi/hr, how many meters per second is that equivalent to?
lesya [120]

Answer:

26.8224 Meters per Second.      

5 0
2 years ago
A positively charged ion will bond with...
irina [24]

Answer:

A

Explanation:

because if you bond postitive and positive they would repell

7 0
3 years ago
Glassblower creating sculptures out of glass physical or chemical
ella [17]

Answer:

phsical

Explanation:

it is a phisical cuz your only changing the shape not the chemical structure

5 0
4 years ago
This set contains the spectra of benzil, biphenyl, and bibenzyl, three compounds used in the melting point experiment. Using you
murzikaleks [220]

Answer:

Spectrum 1- Biphenyl

Spectrum 2 - Benzil

Spectrum 3 - Bibenzyl

Explanation:

<u>For Benzil: </u>

<u> </u>The Spectrum -  2  shows this compound.The C=O and C-H bond stretching observed at following values.

C=O \,at\,1657cm^{-1}

C=H \,at\,3063cm^{-1}

<u> For Biphenyl: </u>

<u> </u>Spectrum -  1  shows this compound.

There are stretching vibrations from 3061, 3032\,and \,1597 -1428cm^{1} due to C-H stretching and C-C stretching respectively of aromatic ring only.

<u>For Bibenzyl: </u>

Spectrum - 3  shows this compound

There are stretching vibrations at 3057,3026 and 1598 - 1449cm^{-1} due to C-H stretching and C-C stretching of aromatic ring.

Along with this, stretching vibrations at 2943 - 2917 cm^{-1}due to C-H of alkyl.

8 0
4 years ago
What is the half-life of iron-59, a radioisotope used medically in the diagnosis of anemia, if a sample with an initial decay ra
Y_Kistochka [10]
1) Data:

<span>initial decay rate, No =16,800 disintegrations/min

final decay rate, Nf = 10,860 disintegrations/min

t = 28.0 days

t half-life =?

2) Formulas

Radioactive disintegration =>

Nt = No * e ^ (-kt)

t half-life = ln (2) / k

3) Solution

From Nt = No * e^ (-kt) =>

Nt / No = e ^ (-kt)

=> -kt = ln (Nt / No)

=> kt = ln (No/Nt)

=> k = ln (No / Nt) / t

=> k = ln (16,800 / 10,860) / 28 days = 0.01558 days^ -1

From t half-life = ln(2) / k

t half-life = ln(2) / (0.01558 days^-1) = 44.5 days.

Answer: 44.5 days.


</span>
8 0
3 years ago
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