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Brilliant_brown [7]
3 years ago
8

All animals make body heat. True or false?

Chemistry
1 answer:
gladu [14]3 years ago
7 0

Answer:

False

Explanation:

Some animals are cold blooded

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1. A gas expands and does p-v work on the surroundings equal to
azamat

The change in energy of the system : -63 J

<h3>Further explanation</h3>

Given

279 J work

216 J heat

Required

The change in energy

Solution

Laws of thermodynamics 1

ΔU=Q+W

Rules :

  • receives heat, Q +  
  • releases heat, Q -  
  • work is done by a system, W -  
  • work is done on a system, W +  

a gas work on the surrounding : W =-279 J

a gas absorb heat from surrounding : Q = +216 J

Internal energy :

= -279+216

= -63 J

3 0
3 years ago
Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.
bonufazy [111]

Answer:

a) 72 °F= 22.22 °C

b)  213.8 °C=  416.84°F

c) 180 °C= 453.15 °K

d) 315 °K=  107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K=  -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

  • Fahrenheit a Celsius: C=\frac{F-32}{1.8}
  • Celsius a Fahrenheit: °F= °C*1.8 + 32
  • Celsius a Kelvin: °K= °C + 273.15
  • Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
  • Fahrenheit a Kelvin:K=\frac{F-32}{1.8} + 273.15

Entonces se obtiene:

a) 72 °F= \frac{72-32}{1.8}=22.22 °C

b)  213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= \frac{1750-32}{1.8} + 273.15= 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

7 0
3 years ago
The element calcium forms the ion Ca2+. How many protons, Neutrons, and electrons does it have?
KonstantinChe [14]

Answer:

18 electrons

20 neutrons

20 protons

Explanation:

4 0
4 years ago
Large hydrocarbons have what characteristics?
QveST [7]
The answer is D because large hydrocarbons have a higher number of carbon which means an increase in boiling point and also rate of flow decreases, so they become solids.
5 0
3 years ago
Compounds A and B are constitutional isomers (same molecular formula but
Naily [24]

Answer:

Trimethylacetaldehyde

Explanation:

For the <u>unknow compound</u> we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does <u>not have nitrogen</u> and we can have several posibilities:

A) C_3H_2O_3

B) C_4H_6O_2

C) C_5H_1_0O

D) C_6H_1_4

If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an <u>oxo group</u> (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, <u>Ketones and aldehydes</u>.

We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very<u> symmetric compound</u>.

By trial an error the find the compound <u>Trimethylacetaldehyde</u> (Figure 1).

3 0
3 years ago
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