Answer:
pH = 12.33
Explanation:
Lets call HA = butanoic acid and A⁻ butanoic acid and its conjugate base butanoate respectively.
The titration reaction is
HA + KOH ---------------------------- A⁻ + H₂O + K⁺
number of moles of HA : 118.3 ml/1000ml/L x 0.3500 mol/L = 0.041 mol HA
number of moles of OH : 115.4 mL/1000ml/L x 0.400 mol/L = 0.046 mol A⁻
therefore the weak acid will be completely consumed and what we have is the unreacted strong base KOH which will drive the pH of the solution since the contribution of the conjugate base is negligible.
n unreacted KOH = 0.046 - 0.041 = 0.005 mol KOH
pOH = - log (KOH)
M KOH = 0.005 mol / (0.118.3 +0.1154)L = 0.0021 M
pOH = - log (0.0021) = 1.66
pH = 14 - 1.96 = 12.33
Note: It is a mistake to ask for the pH of the <u>acid solutio</u>n since as the above calculation shows we have a basic solution the moment all the acid has been consumed.
Answer:
hi
Explanation:
it is confusing lol
but i think that it is C.both
hope it helps
have a nice day
Answer:
Option A is correct. About 5 g of the KClO3 is dissolved
Explanation:
KClO3 is not very good soluble in water.
So, Option C is impossible, because KClO3 is poorly soluble in water.
The low solubility of KClO3 in water causes KClO3 to isolate itself from the reaction mixture by precipitating out of solution.
So, option D will either happen.There will be a part of KClO3 dissolve.
At 10 °C, KClO3 has a solubility of 4.46 g/100 gram (10 °C).
Option A is correct. About 5 g of the KClO3 is dissolved
I have no idea, but i’m pretty sure you gotta divide
