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2 years ago

Which compound contains ionic bonds? 1) N2O 2) Na2O 3) CO 4) CO2

Chemistry

1 answer:

lakkis [162]2 years ago

7 0

Answer:

The ionic bond present between CaO molecule

Explanation:

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What is the unit of Avogadro's number?

kompoz [17]

Answer:

it may be electron, atom or ions depend on the nature of the substance and the character of reaction

like :- particles per mole, coulombs per electron

8 0

3 years ago

During soldering, a mixture of metals ('solder') is heated until it melts. The molten metal falls into the gaps between two piec

Pavlova-9 [17]

Answer:

$31^oC$

Explanation:

Range = Highest value - Lowest value

A 'soft solder' melts between 183 °C and 212 °C.

Melting range of a 'soft solder' = $212-183=29^oC$

A 'hard solder' melts between 620 °C and 680 °C.

Melting range of a 'hard solder' = $680-620=60^oC$

So,

Difference in melting ranges = Melting range of a 'hard solder' - Melting range of a 'soft solder' = $60^oC-29^oC=31^oC$

4 0

4 years ago

A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v

Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

$0.9762bar.\frac{1atm}{1.013bar} =0.9637atm$

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol$

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81 × 10⁻³ moles of M reacted. The molar mass of the metal is:

$\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol$

4 0

4 years ago

what is the trend for the size as you go from Be to Mg to Ca? does the atomic size increase, decrease, or remain the same? how w

lys-0071 [83]

Answer:

the size of Ca is the greatest ,then Mg is the greater on size than Be

Explanation:

if you make the electron configuration for each of the elements, what is the main difference u gonna see ?

Be 4 1s2/2s2

Mg 12 1s2 /2s2 2p6/3s2

Ca 20 1s2 /2s2 2p6/3s2 3p6 3d/4s2

see that all the elements are in the same group but are in different period

u gonna see the last electron valance shell in Ca are too far from its nucleus but in Be the last electrons are too close and more attracted to the atom's nucleus , so the size of Ca is the biggest then Mg then Be

4 0

4 years ago

The closest star to our Sun is Proxima

vichka [17]

Answer:

Distance in kilometre = 4.242 x 10¹² km

Explanation:

Given:

Distance of Proxima Centauri = 4.242 light years

Find:

Distance in kilometre

Computation:

1 light year = 10,000,000,000,000 km

So,

4.242 light years = 4.242 x 10,000,000,000,000

Distance in kilometre = 4.242 x 10¹² km

6 0

3 years ago