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3 years ago

Please help me please please help please

Mathematics

1 answer:

poizon [28]3 years ago

6 0

Answer:

its 2 blurry so i cant help take a better pic and i should be able to help you out

Step-by-step explanation:

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e. 2y(y + 3)this is not a quiz it is an assignment that is due tomorrow and I Wil be grateful for anyhelp

Elena-2011 [213]

We need to multiply

$-2y(y+3)$

We need to use the distributive property to expand this:

$a(b+c)=ab+ac$

Let's multiply it out using this property, to get our answer:

$\begin{gathered} -2y(y+3) \\ =-2y(y)+(-2y)(3) \\ =-2y^2-6y \end{gathered}$

6 0

1 year ago

Help me on dis please

goldfiish [28.3K]

Answer:

3 * 10^-3

Step-by-step explanation:

It is to the negative third power because the decimal needs to move in front of the 3.

7 0

3 years ago

Read 2 more answers

Can someone help me out with this?

Anton [14]

i Think all are correct not sure tho

3 0

3 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

There are five tests in a grading period. A student received grades of 98, 80, and 90, 96 on the first four tests. What grade mu

inn [45]

Answer:

Step-by-step explanation:

The median of the group is 80

If you add all the five numbers up they equal 454 divide by 5 the answer would be 90.8

3 0

3 years ago