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Karolina [17]
2 years ago
9

1. Two balloons are charged with an identical quantity and type of charge: -6.25C. They are held apart at a separation distance

of 0.67m. Determine the magnitude of the electrical force of repulsion between them. I​
Physics
1 answer:
Degger [83]2 years ago
4 0

Answer:

The electric force between them is 878.9 N

Given:

Identical charge C

Separation between two charges  m

For finding the electrical force,

According to the coulomb's law

Here, force between two balloons are repulsive because both charges are same.

Where    N  Therefore, the electric force between them is 878.

Explanation:

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A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area.
babunello [35]

Answer:

True

Explanation:

Pressure is defined as:

p=\frac{F}{A}

where

F is the magnitude of the force perpendicular to the surface

A is the surface

Therefore, pressure is inversely proportional to the area of the surface:

p\propto \frac{1}{A}

this means that, assuming that the forces in the two situations (which have same magnitude) are both applied perpendicular to the surface, the force exerted over the smaller area will exert a greater pressure. Hence, the statement"

<em>"A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area"</em>

is true.

8 0
3 years ago
A positively charged sphere with a charge of 8Q is separated from a negatively charged sphere -2Q by a distance r. There is an a
djverab [1.8K]

Answer:

Explanation:

For the first case , the expression for electrostatic force can be given by the following .

F = K x 8Q x 2Q / r² where k is a constant .

F = K 16 Q² / r²

When they touch , some charge is neutralized . Net charge remaining

= 8Q - 2 Q = 6 Q

Charge on each sphere = 6Q/2 = 3 Q .

Force between them

F₁ = k 3Q x 3 Q / r² = k 9 Q² / r²

F₁ / F = 9 / 16

F₁ = 9 F / 16 .

4 0
3 years ago
block of mass 0.5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50N/m . Th
Alisiya [41]

Answer:

Explanation:

The mass of the block is 0.5kg

m = 0.5kg.

The spring constant is 50N/m

k =50N/m.

When the spring is stretch to 0.3m

e=0.3m

The spring oscillates from -0.3 to 0.3m

Therefore, amplitude is A=0.3m

Magnitude of acceleration and the direction of the force

The angular frequency (ω) is given as

ω = √(k/m)

ω = √(50/0.5)

ω = √100

ω = 10rad/s

The acceleration of a SHM is given as

a = -ω²A

a = -10²×0.3

a = -30m/s²

Since we need the magnitude of the acceleration,

Then, a = 30m/s²

To know the direction of net force let apply newtons second law

ΣFnet = ma

Fnet = 0.5 × -30

Fnet = -15N

Fnet = -15•i N

The net force is directed to the negative direction of the x -axis

8 0
4 years ago
Pressure is about 1000 hPa at sea level and about 500 hPa at an altitude of 5.5 km. Why doesn’t this vertical pressure gradient
saul85 [17]

Answer:

A. The upward pressure gradient force is balanced by gravity.

Explanation:

A. is correct because the pressure difference is actually generated by gravity. As in the following formula for the pressure at different points:

p = p_0 + \rho g h

where p, p_0 are the pressure at 2 points, ρ is the density of the fluid, g is the gravitational constant, and h is the height difference.

B is incorrect because friction in air is too small to make an effect.

C is incorrect because the Coriolis force is horizontal, not vertical.

D is incorrect because a difference of 500 hPa = 50000 Pa, this is half of the atmospheric pressure.

E is incorrect because temperature cannot generate force.

6 0
3 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The
stich3 [128]

Answer:

f = 556.4 N

Explanation:

Mass of the losing player with its all equipment is given as

M = 86 kg

Net force applied on him by another player is given as

F = 780 N

also we know that acceleration of the losing player is given as

a = 2.6 m/s^2

now by Newton's 2nd law we will have

F - f = ma

780 - f = 86(2.6)

780 - f = 223.6

f = 556.4 N

7 0
3 years ago
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