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Furkat [3]
3 years ago
13

A ball rolls along the floor with a constant velocity of 6m/s. How far will it go in 10 sec?

Physics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

60 m

Explanation:

Since it goes 6 m per second, and it goes for 10 seconds, then you'd just multiply 6 x 10, to get that the ball would roll 60 m in 10 seconds.

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Which of the following is a correct step in the process of adding 8.0 x 10^ -2 and 6.0 x 10^ -3
dybincka [34]

Explanation:

In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.

The two terms are:

8.0 \cdot 10^{-2}

6.0 \cdot 10^{-3}

For instance, we can re-write the second term such as it also has a power 10^{-2}. In order to do that, we have to move the decimal point one place to the left, therefore:

6.0 \cdot 10^{-3} = 0.6\cdot 10^{-2}

At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:

8.0\cdot 10^{-2} + 0.6 \cdot 10^{-2} = (8.0 + 0.6) \cdot 10^{-2} = 8.6\cdot 10^{-2}

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3 years ago
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zhannawk [14.2K]

Answer:

B

Explanation:

6 0
3 years ago
A 10- kg ball starting from rest rolls down a 5 m tall smooth hill from one person to another person who is standing at the bott
olya-2409 [2.1K]

Answer: 3.13 m

Explanation:

Given

mas of the ball is m=10 kg

The ball rolls down a vertical distance of 5 m

Spring constant of spring is k=100\ N/m

Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy

\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m

Thus, the spring compresses by 3.13 m.

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