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Bas_tet [7]
3 years ago
13

Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull th

e rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.
1.6 × 104 J
3.5 × 104 J
5.8 × 104 J
9.0 × 104 J
Physics
2 answers:
leva [86]3 years ago
5 0

Answer:

Explanation:

2021

Mariulka [41]3 years ago
4 0

Answer:

Explanation:

Remark

The only thing that might trip you up is what to do with the angle. The vertical component of the 15 degrees does no work against anything. So the 15 degrees limits the horizontal force.

The formula is

Work = F * d * cos(15)

The givens are

F = 2000 N

d = 30 m

Cos(15) = 0.9659

Solution

Work = 2000 * 30 * cos(15)

Work = 57,955

Rounded to two places would be 5.8 * 10^4

C

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Explanation:

A black hole is a place in space where gravity pulls so much that even light can not get out. The gravity is so strong because matter has been squeezed into a tiny space. This can happen when a star is dying.

Because no light can get out, people can't see black holes. They are invisible. Space telescopes with special tools can help find black holes. The special tools can see how stars that are very close to black holes act differently than other stars.

6 0
3 years ago
Read 2 more answers
A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?
lesantik [10]
Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3
6 0
3 years ago
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What is the momentum of an object with 5.22 kg and 1.7 m/s
BlackZzzverrR [31]

Answer:

8.874

Explanation:

You need to times 5.22 kg and 1.7 m/s to get 8.874.

8 0
3 years ago
Which the answer It's science
earnstyle [38]
The answer is A. ive done a 5-k race, so its for sure 3 miles. 
3 0
3 years ago
If the sprinter accelerates at that rate for a distance of 15 m, and then maintains the velocity he has at that point for the re
ahrayia [7]

Answer:

The time for the entire race is 11.39 sec.

Explanation:

Given that,

Distance = 15 m

Remainder distance = 100 m

Suppose A sprinter begins a race with an acceleration of 3.4 m/s².

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value in the equation

15=0+\dfrac{1}{2}\times3.4\times t^2

t^2=\dfrac{30}{3.4}

t=2.97\ sec

We need to calculate the final velocity of sprinter

Using equation of motion again

v=u+at

Put the value into the formula

v=0+3.4\times2.97

v=10.09\ m/s

We need to calculate the distance covers by sprinter

d=100-15=85\ m

The sprinter need to covers only 85 m.

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t'=\dfrac{85}{10.09}

t'=8.42\ sec

We need to calculate the time for the entire race

t''=t+t'

Put the value into the formula

t''=2.97+8.42

t''=11.39\ sec

Hence, The time for the entire race is 11.39 sec.

4 0
3 years ago
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