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2 years ago

6

In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro

m left to right at 1.79 m/s. Almost simultaneously, the other chef launches a 335 g veggieburger (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head on at the given speeds. The counter is practically friction free due to accumulated grease. The two delicacies merge into a single, unbelievably savory serving.A. In what direction does the delectible dish move, if it moves at all?B. At what speed does it move? Enter a positive number.

1 answer:

Murrr4er [49]2 years ago

3 0

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒ $m_1v_1+m_2v_2=(m_1+m_2)v$

then,

⇒ $v=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

On substituting the values, we get

⇒ $=\frac{201\times 1.79+335\times (-2.47)}{201+335}$

⇒ $=\frac{359.79-827.45}{536}$

⇒ $=\frac{-467.66}{536}$

⇒ $=-0.8725$ (to the left)

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(b) Figure 4 shows a car travelling on a motorway.

Alik [6]

Answer:

To calculate anything - speed, acceleration, all that - we need <em>data</em>. The more data we have, and the more accurate that data is, the more accurate our calculations will be. To collect that data, we need to <em>measure </em>it somehow. To measure anything, we need tools and a method. Speed is a measure of distance over time, so we'll need tools for measuring <em>time </em>and <em>distance</em>, and a method for measuring each.

Conveniently, the lamp posts in this problem are equally spaced, and we can treat that spacing as our measuring stick. To measure speed, we'll need to bring time in somehow too, and that's where the stopwatch comes in. A good method might go like this:

Press start on the stopwatch right as you pass a lamp post
Each time you pass another lamp post, press the lap button on the stopwatch
Press stop after however many lamp posts you'd like, making sure to hit stop right as you pass the last lamp post
Record your data
Calculate the time intervals for passing each lamp post using the lap data
Calculate the average of all those invervals and divide by 40 m - this will give you an approximate average speed

Of course, you'll never find an *exact* amount, but the more data points you have, the better your approximation will become.

5 0

2 years ago

What is the magnitude of vector K ?

vovangra [49]

Answer:

Vector K = 8 m

Explanation:

The given figure shows a right angle triangle JKL. It is given that :

vector L = 10 m

vector J = 6 m

We have to find vector k. We can find it by using Pythagoras theorem. According to this theorem, the sum of squares of perpendicular and the base is equal to the square of the longest side.

$L^2=K^2+J^2$

$K^2=L^2-J^2$

$K^2=(100)^2-(6)^2$

K = 8 m

Hence, the magnitude of vector K is 8 m.

3 0

3 years ago

1. Which of the following is an example of deduction? a. Hector calls the weather service to find out if the temperature outside

Ann [662]

Answer:

b

Explanation:

she made a conclusion based off of her own observation, and isnt dumb enough to call a weather station

5 0

3 years ago

Not including thinking distance, lawful brakes must stop a car at 20 miles per hour within how many feet?

Svetradugi [14.3K]

Answer:

B. 25 feet

Explanation:

In most cities in US, passenger car brakes must stop a car moving at 20 miles per hour at 25 feet.

Therefore, the correct option is "B" 25 feet

5 0

3 years ago

Read 2 more answers

. If a pendulum-driven clock gains 5.00 s/day, what fractional change in pendulum length must be made for it to keep perfect tim

inn [45]

Answer:

The appropriate response will be "Length must be increased by 0.012%".

Explanation:

The given values is:

ΔT = 5 s/day

Now,

⇒ $\frac{\Delta T}{T} =\frac{5}{24\times 60\times 60}$

On multiplying both sides by "100", we get

⇒ $\frac{\Delta T}{T}\times 100 =\frac{500}{24\times 60\times 60}$

⇒ $\frac{\Delta T}{T}\times 100=0.005787$ (%)

∵ $T=2\pi\sqrt{\frac{l}{g} }$

On substituting the values, we get

⇒ $\frac{\Delta T}{T}$ % = $\frac{1}{2}\times \frac{\Delta l}{l}$ %

On applying cross multiplication, we get

⇒ $\frac{\Delta l}{l}$ % = $2\times \frac{\Delta T}{T}$ %

⇒ = $2\times 0.05787$

⇒ = $0.011574$

⇒ = $0.012$ %

6 0

3 years ago