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padilas [110]
2 years ago
6

In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro

m left to right at 1.79 m/s. Almost simultaneously, the other chef launches a 335 g veggieburger (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head on at the given speeds. The counter is practically friction free due to accumulated grease. The two delicacies merge into a single, unbelievably savory serving.A. In what direction does the delectible dish move, if it moves at all?B. At what speed does it move? Enter a positive number.
Physics
1 answer:
Murrr4er [49]2 years ago
3 0

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒  m_1v_1+m_2v_2=(m_1+m_2)v

then,

⇒  v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

On substituting the values, we get

⇒     =\frac{201\times 1.79+335\times (-2.47)}{201+335}

⇒     =\frac{359.79-827.45}{536}

⇒     =\frac{-467.66}{536}

⇒     =-0.8725 (to the left)

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Answer:

The speed of the wave with a frequency 100 mhz will be  3\times 10^{8}m/sec

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find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²
Ierofanga [76]

Answer:

T_{m } = 4.86 s

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Explanation:

<u><em>Given:</em></u>

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Acceleration due to gravity of Earth = g_{e} = 10 m/s²

<u><em>Required:</em></u>

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T = 2π \sqrt{\frac{l}{g} }

<u><em>Solution:</em></u>

<u>For moon</u>

<em>Putting the givens,</em>

T = 2(3.14) \sqrt{\frac{1}{1.67} }

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T = 6.3 × 0.77

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<em>Putting the givens</em>

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At the highest trophic level, the the least available energy in kilojoules in this food web is found.

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