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Ludmilka [50]
2 years ago
7

Expand (x-2)^7 using binomial theorem​

Mathematics
2 answers:
umka2103 [35]2 years ago
4 0

Answer:

Urr answer...

Step-by-step explanation:

<h3 /><h3 /><h3 /><h3 /><h3>i hope its help to you ✌</h3>

Romashka-Z-Leto [24]2 years ago
4 0

Answer:

x^7-14x^6+84x^5-280x⁴+560x³-672x²+256x-128

Step-by-step explanation:

7C0•x^7+7C1•x^6•-2+7C2•x^5(-2)²+7C3•x⁴(-2)³+7C4•x³(-2)⁴+7C5•x²(-2)^5+7C6•x(-2)^6+7C7(-2)^7

=>x^7+7x^6(-2)+21x^5(4)+35x⁴(-8)+35x³(16)+21x²(-32)+7x(64)-128

=>x^7-14x^6+84x^5-280x⁴+560x³-672x²+256x-128

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Describe a way to check the correctness of a subtraction answer.
Tamiku [17]

Step-by-step explanation:

Well in general, we can represent subtraction as: x-y=z

"z" represents the difference, and it really just represents x with y taken away. So if we were to "give back" this y value, we should get "x".

This means that: z+y=x

So one way to check, is adding the value that's being subtracted (y value) and the difference (z value), this should get you the value that is being subtracted from (x value). If you don't get the original value that's being subtracted from (x-value) then you know the answer you got is wrong.

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1 year ago
What does increase mean
Darya [45]
Increase- to be more significant in value, to be of more worth, to have a larger quantity.

Basically, if I said I added 2 to 5, that would be an increase.

2+5=7 7 is bigger than 5. 

If I subtracted 2 from 5, that would make a decrease in value.

5-2=3  3 is smaller than 5.

I hope this helps!
~kaikers 
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3 years ago
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jeyben [28]

Answer:

<h2>In a quadrilateral, opposite angles are congruent.</h2>

Step-by-step explanation:

Angle B & D are both opposite to each other, yet congruent.

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Find an equation of the line l that contains the points left parenthesis 0 comma 0 right parenthesis(0,0) and left parenthesis 3
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3 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
3 years ago
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