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jolli1 [7]
4 years ago
13

The figure shows a circle inscribed in a triangle. To construct the inscribed circle, angle bisectors were first constructed at

each angle of the triangle. Which happened next? A circle was constructed using the intersection of the angle bisectors as the center of the circle and the obtuse vertex as a point on the circumference of the circle. A circle was constructed using a vertex as the center of the circle and the intersection of the angle bisectors as a point on the circumference of the circle. Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed. Segments bisecting each side of the triangle were constructed through the intersection of the angle bisectors.
Mathematics
2 answers:
klemol [59]4 years ago
7 0

Answer:

Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

The above choice represents a bit of excess work. Actually, only one such perpendicular line segment needs to be constructed in order to determine the radius of the inscribed circle.

Once you know the center and radius, you can construct the inscribed circle.

bearhunter [10]4 years ago
5 0

Answer:

C.Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

100%

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Any help appreciated
sergij07 [2.7K]

Answer:

2677

Step-by-step explanation:

Let's make this easier first of all:

a^2-y^3(a-y^2)y^2

a^2-y^5(a-y^2)

a^2-ay^5+y^7

(-2)^2-(-2)(3)^5+3^7

4-(-2*243)+2187

4-(-486)+2187

4+486+2187

490+2187

2677

6 0
3 years ago
Read 2 more answers
The data below shows the selling price (in hundred thousands) and the list price (in hundred thousands) of homes sold. Construct
fredd [130]

Answer:

Since the calculated t= 7.8120 falls in the critical region ≥ 2.306 we reject H0 and conclude that there is a linear correlation between the two variables.

Step-by-step explanation:

We see that r²= 0.981 and r= 0.995 from the figure .

The P- value is less than 0.05  which indicates that the two variables are linearly correlated.

Set up the hypothesis as

H0: β= 0 i.e the two variables X and Y are not related

Ha: β≠0 i.e the two variables are related

The significance Level is set at ∝=0.05

The test statistic , if H0 is true is

t= b/sb

where sb² = s²yx / ∑( x-x`)² = ∑( y-y`)²/n-2 ∑( x-x`)²

assuming that the distribution of Yi for each Xi is normal with the same mean and the same standard deviation , the statistic t conforms to the Student's t distribution with n-2= 8 degrees of freedom

(X - x`)2                 (X - x`)(Y - y`)                       (Y - y`)2

265.69                   259.17                         15.9²=252.81

7174.09                 6953.87                       -82.1²=6740.41

75.69                       87.87                            -10.1=102.01

2052.09                 1671.57                           36.9²=1361.61

4529.29                 5848.37                        86.9²=7551.61

8335.69                7294.87                          79.9²=6384.01

4998.49                5380.27                        -76.1²=5791.21

1069.29                 1016.97                          -31.1=967.21

1043.29                   1159.57                         35.9²=1288.81

<u>3102.49                    3124.77                        -56.1²=3147.21</u>

<u>SS: 32646.1            SP: 32797.3                        33,586.9</u>

<u />

Sum of X = 3877

Sum of Y = 3991

Mean X = 387.7

Mean Y = 399.1

Sum of squares (SSX) = 32646.1

Sum of products (SP) = 32797.3

b = SP/SSX = 32797.3/32646.1 = 1.00463

a = Y` - bX `= 399.1 - (1*387.7) = 9.60437

Syx= √∑(y-y`)²/n-2= 33,586.9/8= 4198.3625

sb= syx/ √∑(x-x`)²=4198.3625/32646.1 =0.12860

Putting the values in the regression equation

ŷ = bX + a

ŷ = 1.00463X + 9.60437

The critical region is t ≥ t (0.025) (8)= 2.306

t= b/ sb= 1.00463/ 0.12860=7.8120

Since the calculated t= 7.8120 falls in the critical region ≥ 2.306 we reject H0 and conclude that there is a linear correlation between the two variables.

4 0
3 years ago
Evelyn is making a costume for her school play. She needs to buy 2 yards of cotton fabric at a cost of $3.49 per yard, and 1/2 y
Elanso [62]
Round 3.49 to 3.50
multiply by 2: 7 dollars
round 5.98 to 6.00
multiply by 1/2: 3 dollars
7 dollars +3 dollars= 10 dollars
She will have enough money
7 0
3 years ago
Karen wrote 2/3 of her essay in 1/6 of an hour. How long will it take her to write the full essay
777dan777 [17]

Answer:

3/12 of an hour or 15 minutes

Step-by-step explanation:

1/6 divided by 2 1/12 times 3 for 1/3 is 3/12

4 0
3 years ago
PLEASE HELP ME
mafiozo [28]

Answer:

1) SAT average divided by budget per student

Graduation rate divided by budget per student

2) No. The definitions have opposite results

Step-by-step explanation:

did it on khan academy

4 0
3 years ago
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