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jolli1 [7]
4 years ago
13

The figure shows a circle inscribed in a triangle. To construct the inscribed circle, angle bisectors were first constructed at

each angle of the triangle. Which happened next? A circle was constructed using the intersection of the angle bisectors as the center of the circle and the obtuse vertex as a point on the circumference of the circle. A circle was constructed using a vertex as the center of the circle and the intersection of the angle bisectors as a point on the circumference of the circle. Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed. Segments bisecting each side of the triangle were constructed through the intersection of the angle bisectors.
Mathematics
2 answers:
klemol [59]4 years ago
7 0

Answer:

Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

The above choice represents a bit of excess work. Actually, only one such perpendicular line segment needs to be constructed in order to determine the radius of the inscribed circle.

Once you know the center and radius, you can construct the inscribed circle.

bearhunter [10]4 years ago
5 0

Answer:

C.Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

100%

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A=7.5<br> B=30<br> C=15 square of 2<br> D= 15
Inessa [10]

I think the awnser is B=30

5 0
3 years ago
F( x) = 8x – 9 when x=3
Elan Coil [88]

Answer:

f = 5, x = 3.

Step-by-step explanation:

8x = 24

24 - 9 = 15.

3(5) = 15.

hope this helps.

3 0
2 years ago
Read 2 more answers
What are the numbers of symmetries for this figure?
mrs_skeptik [129]

Answer:

rotational symmetry: 2

reflectional symmetry: 0

Step-by-step explanation:

I took the test

8 0
3 years ago
Quadrilateral PUMA has coordinates at P(-5,-2), U(-1,2), M(4,-3), A(0,-7) and it is transformed by (x+3,y-5). Determined the ima
IgorLugansk [536]

The image of M is (7 , -8)

Step-by-step explanation:

Let us revise some transformation

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

∵ The quadrilateral PUMA has coordinates at:

   P (-5 , -2) , U (-1 , 2) , M (4 , -3) , A (0 , -7)

∵ It is transformed by (x + 3 , y - 5)

- That means the quadrilateral translated 3 units right and 5 units

   down, then we add each x-coordinate by 3 and subtract 5 from

   each y-coordinate

∵ The coordinates of point M are (4 , -3)

∴ The image of point M = (4 + 3 , -3 - 5)

∴ The image of point M = (7 , -8)

The image of M is (7 , -8)

Learn more:

You can learn more about transformation in brainly.com/question/5563823

brainly.com/question/11203617

*LearnwithBrainly

8 0
3 years ago
How to solve this? ​
nevsk [136]

Answer:

Answer of 17 is ㏒(x^{2}+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is  x = -㏒12/㏒8 and Answer of 39 is x = 5

Step-by-step explanation:

17. ㏒x + ㏒(x+15)

     Using property ㏒a + ㏒b = ㏒a×b

     ∴ ㏒x + ㏒(x+15)

        ㏒x×(x+15)

        ㏒(x^{2}+15x)

        The answer is ㏒(x^{2}+15x)

33. 2^(x-5) = 8

     2^(x-5) = 2^3

      Using property 2^a = 2^b

      Then a = b

     ∴x-5 = 3

       x = 8

      The answer is x = 8

35. 2^x = 10

    Taking log on both sides gives

     ㏒2^x = ㏒10

     x×㏒2 = ㏒10

     x = ㏒10/㏒2

    The answer is x = ㏒10/㏒2

37. 8^-x = 12

    Taking log on both sides gives

     ㏒8^-x = ㏒12

     -x×㏒8 = ㏒12

      x = -㏒12/㏒8

    The answer is  x = -㏒12/㏒8

39. 5(2^3 × x) = 8

      5(8×x) = 8

      x = 5

    The answer is x=5

 

5 0
4 years ago
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