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jolli1 [7]
4 years ago
13

The figure shows a circle inscribed in a triangle. To construct the inscribed circle, angle bisectors were first constructed at

each angle of the triangle. Which happened next? A circle was constructed using the intersection of the angle bisectors as the center of the circle and the obtuse vertex as a point on the circumference of the circle. A circle was constructed using a vertex as the center of the circle and the intersection of the angle bisectors as a point on the circumference of the circle. Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed. Segments bisecting each side of the triangle were constructed through the intersection of the angle bisectors.
Mathematics
2 answers:
klemol [59]4 years ago
7 0

Answer:

Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

The above choice represents a bit of excess work. Actually, only one such perpendicular line segment needs to be constructed in order to determine the radius of the inscribed circle.

Once you know the center and radius, you can construct the inscribed circle.

bearhunter [10]4 years ago
5 0

Answer:

C.Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

100%

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Step-by-step explanation:

You are looking for the composite g(f(2)). The simplest way to solve this is to evaluate f(2) and enter the solution in to your g function.

g(f(2))=g(-(2)^2-2(2)+4)=g(-4-4+4)=g(-4)

g(-4)=4/(-4(-4)-2)=4/(16-2)=4/14=2/7

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g(f(2))=4/(-4(-4)) -2=4/16 -2=1/4 -2=1/4-8/4= -7/4

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