Answer: 143.66 grams of M (g) is contained in 396 g of the mineral
Explanation:
Given : mineral contains metal M and sulphur
Mass of mineral = 4.3 g
Mass of metal M in mineral = 1.56 g
Thus if 4.3 gram of mineral contains metal = 1.56 g
Using unitary method for solving this :
1 g of mineral contains metal =
396 g of mineral contains metal =
Thus 143.66 grams of M (g) is contained in 396 g of the mineral
Based on the scenario, that is not needed to calculate the mass of the calcium oxide is : D. the volume of the unknown mass
In order to find out the mass of a product, you just need the mass of the reactants and the mass of the product
hope this helps
Mg reducing agent and Cu oxidising agent.
Aldehydes and ketones having
α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH).
The initial product formed during this reaction is
β-hydroxy alcohol, which then undergoes dehydration to form
α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. The complete reaction product formed is shown below.
D. this is the correct answer because the question is showing a comparison of sizes rather than the actual sizes which eliminates B. A and C have no relevance.
