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jonny [76]
2 years ago
8

NO LINKS PLS!!! AND I WILL MARK THE BRAINEST ANSWER

Chemistry
1 answer:
Masja [62]2 years ago
5 0

Answer:

(H2O)n

raduim hydroxide

hBr

carbonic acid

Explanation:

You might be interested in
5F248+ 2NH3(8) ► NF418 + 6HF
mylen [45]

Answer:

14.2L at STP

Explanation:

Based on the problem, 2 moles of NH3 produce 6 moles of HF. To solve this question we have to convert the mass of NH3 to moles. With the chemical equation find the moles of HF and using PV = nRT find the liters of HF:

<em>Moles NH3 -Molar mass: 17.031g/mol-</em>

3.6g NH3 * (1mol / 17.031g) = 0.211 moles NH3

<em>Moles HF:</em>

0.211 moles NH3 * (6mol HF / 2mol NH3) = 0.634 moles HF

<em>Volume HF</em>

PV = nRT; V = nRT/P

<em>Where V is volume in liters, n are moles of the gas = 0.634 moles, R is gas constant = 0.082atmL/molK, T is absolute temperature = 273.15K at STP and P is pressure = 1atm at STP.</em>

Replacing:

V = 0.634moles*0.082atmL/molK*273.15K / 1atm

V = 14.2L at STP

6 0
2 years ago
A solution contains 14 grams of KCl in 100. grams of water at 40°C. What is the minimum amount of KCl that must be added to make
pashok25 [27]

Answer:

1386g

Explanation:

Solubility of a solute is the ability of the solute to mix into a liquid (the solvent). It measures the highest amount of substance mixed into a liquid solvent while they are both at equal amounts.

if 14g dissolved in 100cm3

  the amount that will dissolve in 1000cm3 = 14 x 1000/ 100

                                                                      =1400g

To form a saturated solution, 1400 - 14 = 1386g must be added.

8 0
2 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Br2(l) and I-(aq) Use the reduction po
Vikki [24]

Answer:

1.58×10E18

Explanation:

Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.

E°cell= 1.07- 0.53= 0.54 V

E°cell= 0.0592/n logK

0.54 = 0.0592/2 logK

logK= 0.54/0.0296

logK= 18.2

K= Antilog (18.2)

K= 1.58×10^18

3 0
3 years ago
HELP PLZ
Vaselesa [24]

Answer:

Scientific Explanation of weather change and cause storms is described below in detail.

Explanation:

The weather is just the nature of the environment at any time, including items such as warmth, rainfall, air pressure, and cloud shelter. Daily variations in the weather are due to storms and winds. Seasonal variations are due to the Earth spinning nearby the sun. Warm beginnings often produce stormy weather as the heated air mass at the exterior rises above the cool air mass, creating clouds and storms.

4 0
3 years ago
The valences of metal x,y and z are 1,2 and 3 respectively. What are the formulae of their;a) hydroxides, b) sulphates, c) hydro
Rina8888 [55]

Answer:

See answer below

Explanation:

AS we know that the valence for those metals X, Y, and Z are 1, 2 and 3, we can determine the formula of each compound.

1. Hydroxides.

An hydroxide is formed when an oxyde of a metal reacts with water. When this happens, the general molecular formula is:

Meₐ(OH)ₙ

Where:

a: valence or charge of the hydroxide (Which is -1)

n: valence of the metal.

Following this, the formula for X, Y and Z would be:

XOH

Y(OH)₂

Z(OH)₃

2. Sulphates

Sulphates follow a similar rule of hydroxide in the general molecular formula, but instead of having a charge of -1, it has a charge of -2 so:

Mₐ(SO₄)ₙ

So, following the rule:

X₂SO₄

Y₂(SO₄)₂ ------> YSO₄

Z₂(SO₄)₃

3. Hydrogens

Following the same rule as the previous, hydrogens works with a charge of -1, so:

MₐHₙ

Then:

XH

YH₂

ZH₃

4. Carbonates.

This follows the same rule as sulphates, with the same charge so:

Mₐ(CO₃)ₙ

Then:

X₂CO₃

YCO₃

Z₂(CO₃)₃

5. Nitrates

Follow the same rule as the hydroxides, with the same charge of -1.

Mₐ(NO₃)ₙ

Then:

XNO₃

Y(NO₃)₂

Z(NO₃)₂

6. Phosphates

In the case of phosphates, these have a charge of -3 so:

Mₐ(PO₄)ₙ

Then:

X₃PO₄

Y₃(PO₄)₂

Z₃(PO₄)₃ ----> ZPO₄

Hope this helps

6 0
2 years ago
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