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3 years ago

List the exceptions to Metals showing a high density?

Chemistry

1 answer:

Bumek [7]3 years ago

7 0

Answer:

Osmium, 22.6 g/cc.

Iridium, 22.4 g/cc.

Platinum, 21.45 g/cc.

Rhenium, 21.2 g/cc.

Uranium, 20.2 g/cc.

these are are metals having a high density

Explanation:

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What is the uncertian digit in 0.054 g

UkoKoshka [18]

Answer:

5.4g

Explanation:

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3 years ago

A geochemist measures the concentration of salt dissolved in Lake Parsons, an isolated salt lake. He finds a concentration of 21

VikaD [51]

Answer:

68,2%

Explanation:

Supposing the initial salt concentration of lake Parsons is the same of non-isolated lakes, 6,67L, and the change of salt concentration in isolated lake is just for water evaporation it is possible to write:

6,67gL⁻¹×X = 21gL⁻¹×Y

-Where X is the initial water and Y is the water that remains in the isolated lake-

Thus:

6,67X = 21Y

0,318 = Y/X

0,318 is the ratio of water that remains between total water. To obtain the ratio of evaporated water:

1-0,318 = 0,682

In percentage: 68,2%

I hope it helps!

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3 years ago

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ZanzabumX [31]

C
Explanation- equals 459

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3 years ago

In cellular chemical pathways, the product(s) of any particular reaction are often quickly consumed by the next reaction in the

mezya [45]

Answer:

Tend to keep the product concetration low and therefore drive the reaction righward

Explanation:

The fact the products of a reaction are quickly consumed by the next one would tend to keep the product concetration low and therefore drive the reaction righward (to the products).

This happens because the system will not achive equilibrium between the reactants and the product, and will keep producing it util the system achives equilibrium or the reactants dry out.

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3 years ago

A propane stove burned 470 grams propane and produced 625 grams of water (this is the actual yield) C3H8 +5O2=3CO2+4H20. What wa

Liula [17]

Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

theoretical yield of H2O = 769.09g

Percentage yield of water (H2O) =?

Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

Therefore, the percentage yield of water (H2O) is 81.3%

4 0

3 years ago