Meiosis goes through 2 divisions to create four unique haploid cells. true or false

Chemistry

1 answer:

Aleksandr [31]2 years ago

7 0

Answer:

True

Explanation:

True is the ANSWER.

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Calculate the mass percent of copper in cus, copper(ii) sulfide. if you wish to obtain 10.0g of copper metal from copper(ii) sul

Aleksandr [31]

Using the relative atomic weights of both copper and sulfur ie copper = 63.55 and sulfur is 32.06 so 63.55+32.06=95.56 total mass and so of this, copper = 63.55/95.56=66.4%. So to get 10 grams of copper, use the formula 10g=66.4%xCuS so CuS=10/0.664=15.06 grams of CuS.

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3 years ago

What is the hybridization of carbon in nco-?

Svet_ta [14]

First let us see what kind of bonds are formed in the compound. By drawing the structure, we see that the kind of bonds are:

N =- triple bond -= C – O

<span>So there is only single bond between C and O therefore the hybridization of C is sp.</span>

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3 years ago

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When using ion-selective electrodes, to compensate for a complex or unknown matrix, the _____________ method can be used to dete

VMariaS [17]

When using ion-selective electrodes, to compensate for a complex or unknown matrix, the standard addition method can be used to determine the analyte concentration. Option D

<h3>What are ion-selective electrodes?</h3>

Analytical chemistry is a science that deal with the measurement and detection of the accurate amount of a substance. Analytical chemistry plays a large role in environmental management as it helps in the determination of the levels of contaminants in a sample.

An ion selective electrode is used in analytical chemistry to measure the amount of a target ion by converting its activity into a measurable electrical signal.

Hence, when using ion-selective electrodes, to compensate for a complex or unknown matrix, the standard addition method can be used to determine the analyte concentration.

Learn more about ion-selective electrodes:brainly.com/question/14987024

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