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IgorC [24]
2 years ago
10

Only valence electrons can be shared stolen or given away True False

Chemistry
2 answers:
Vesna [10]2 years ago
5 0

Answer:

false

Explanation:

idk

Flura [38]2 years ago
3 0

Answer:

true

Explanation:

trust me

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Rudiy27

Answer:

whats ur question

Explanation:

3 0
3 years ago
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-1.42, 3, 32.5%, √4, 2³, −0.375, 3/8 as a decimal least to greatest
nignag [31]

Answer:

-1.42, -0.375, 32.5% (.325), 3/8 (.375), √4 (2.0), 3 (3.0), 2³ (8.0)

8 0
1 year ago
A sample of O2 gas (2.0 mmol) effused through a pinhole in 5.0 s. It will take __________ s for the same amount of CO2 to effuse
ludmilkaskok [199]

Answer:

\large \boxed{\text{5.9 s}}

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases, the ratio of their rates of effusion is

\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

The time for diffusion is inversely proportional to the rate.

\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}

Let CO₂ be Gas 1 and O₂ be Gas 2

Data:

M₁ = 44.01

M₂ = 32.00

Calculation

\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}

4 0
3 years ago
Type the correct answer in the box. The pressure inside a tire is measured as 28.0 . What is its pressure in ? 1 pound = 4.45 ne
posledela

The pressure is 19.3 N/cm².

<em>p</em> = (28.0 lb/1 in²) × (4.45 N/1 lb) × (1 in²/6.45 cm²) = 19.3 N/cm²

8 0
3 years ago
How is kinetic energy related to mass and velocity?
Andrew [12]
The amount of kinetic energy that an object has depends on its mass or how heavy it is and how fast it is moving, or velocity
4 0
2 years ago
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