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stepan [7]
3 years ago
10

A car has a uniform acceleration of 5 m/s2. What distance will it cover in 10 s after start​

Physics
1 answer:
amm18123 years ago
3 0

Answer:

Therefore, the car will cover a distance of 200 meters after 10 seconds.

<h2>Please mark me as brainliest</h2>
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The free-body diagram below represents the force of several vehicles driving across a bridge. Assume that the bridge is in stati
krek1111 [17]

In order to calculate the unknown reaction force, we need to know that the sum of forces pointing down is equal the sum of the forces pointing up, so all forces will be in equilibrium.

So we have:

\begin{gathered} 17800+150000+13200=121000+x \\ 181000=121000+x \\ x=181000-121000 \\ x=60000 \end{gathered}

7 0
1 year ago
A conductor carrying a conventional current in the positive-x direction is in a magnetic field whose vector points in the positi
a_sh-v [17]

Answer:

Positive Z direction (out of screen)

Explanation:

Magnetic force is given by F = il \wedge B. A quick way to gauge the components is to put your left middle finger on the direction of the current, your index on the direction of the magnetic field, and the thumb gives you the answer you want.

4 0
3 years ago
Read 2 more answers
A solenoidal coil with 25 turns of wire is wound tightly aroundanother coil with 300 turns. The inner solenoid is 25.0 cm long a
Aneli [31]

Answer:

(a). The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Explanation:

Given that,

Number of turns of coil = 25

Number of turns of another coil = 300

Length = 25.0 cm

Diameter = 2.00 cm

Current = 0.120 A

Rate \dfrac{di_{2}}{dt}=1.75\times10^{3}\ A/s

(a). We need to calculate the magnetic field due to inner solenoid

Using formula of magnetic field

B=\mu_{0}(\dfrac{N_{2}}{l})I

Put the value into the formula

B=4\pi\times10^{-7}\times(\dfrac{300}{0.25})\times0.120

B=1.81\times10^{-4}\ T

We need to calculate the average magnetic flux through each turn of the inner solenoid

Using formula of magnetic flux

\phi=B\cdot A

Put the value into the formula

\phi=1.81\times10^{-4}\times\pi\times (1.00\times10^{-2})^2

\phi=5.68\times10^{-8}\ Wb

The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). We need to calculate the mutual inductance of the two solenoids

Using formula of mutual inductance

M=\dfrac{N_{1}\phi}{i_{1}}

Put the value into the formula

M=\dfrac{25\times5.68\times10^{-8}}{0.120}

M=0.00001183\ H

M=1.183\times10^{-5}\ H

The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c).  We need to calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

Using formula of emf

\epsilon=-M\dfrac{di_{2}}{dt}

Put the value into the formula

\epsilon=-1.183\times10^{-5}\times1.75\times10^{3}

\epsilon=-0.0207\ V

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Hence, (a). The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

5 0
3 years ago
As an astronaut travels from the surface of Earth to a position that is four times as far away from the center of Earth, based o
nirvana33 [79]

Answer:

Yes

Explanation:

3 0
4 years ago
A 0.180 kg ball falls 2.5 m. How much work does the force of gravity do on the ball?
kifflom [539]

The amount of work done by the force of gravity on the ball is 4.41 Joules.

<u>Given the following data:</u>

  • Mass of ball = 0.180 kg.
  • Displacement = 2.5 meters.

<u>Scientific data:</u>

  • Acceleration due to gravity = 9.8 m/s^2.

To calculate the amount of work done by the force of gravity on the ball:

<h3>How to calculate work done.</h3>

In Science, work done is calculated by multiplying force and the height or displacement experienced by an object.

Mathematically, work done is given by the formula:

Work\;done = force \times displacement = mgh

Substituting the given parameters into the formula, we have;

Work\;done = 0.180 \times 9.8 \times 2.5

Work done = 4.41 Joules.

Read more on work done here: brainly.com/question/22599382

6 0
2 years ago
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