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3 years ago

A 0.180 kg ball falls 2.5 m. How much work does the force of gravity do on the ball?

Physics

1 answer:

kifflom [539]3 years ago

6 0

The amount of work done by the force of gravity on the ball is 4.41 Joules.

<u>Given the following data:</u>

Mass of ball = 0.180 kg.

Displacement = 2.5 meters.

<u>Scientific data:</u>

Acceleration due to gravity = 9.8 $m/s^2$ .

To calculate the amount of work done by the force of gravity on the ball:

<h3>How to calculate work done.</h3>

In Science, work done is calculated by multiplying force and the height or displacement experienced by an object.

Mathematically, work done is given by the formula:

$Work\;done = force \times displacement = mgh$

Substituting the given parameters into the formula, we have;

$Work\;done = 0.180 \times 9.8 \times 2.5$

Work done = 4.41 Joules.

Read more on work done here: brainly.com/question/22599382

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A tennis ball is thrown with a downward velocity of 2.00m/s off a cliff. It takes 6.10 seconds for it to hit the ground. How tal

tatyana61 [14]

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3 years ago

The paper dielectric in a paper-and-foil capacitor is 0.0800 mm thick. Its dielectric constant is 2.50, and its dielectric stren

jeka94

Answer:

a) 0.723 m²

b) 2000V

Explanation:

Given that

Thickness of the capacitor, d = 0.08*10^-3 m

Dielectric constant of the capacitor, k = 2.5

Dielectric strength of the capacitor, E = 50*10^6

Capacitance of the capacitor, C = 0.2*10^-6

Permittivity of free space, E• = 8.85*10^-12

The area, A is given by the formula

A = (C * d) / (k * E•)

A = (0.2*10^-6 * 0.08*10^-3) / (2.5 * 8.85*10^-12)

A = 1.6*10^-11 / 2.213*10^-11

A = 0.723 m²

Potencial difference, V is given by the formula

V = E * d

V = 1/2 * 50*10^6 * 0.08*10^-3

V = 1/2 * 4000

V = 2000 V

8 0

4 years ago

*Urgent* I WILL GIVE BRAINLIEST

Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school both take up energy, unlike walking to school.

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3 years ago

The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to Earth's Moon. Their orbital radii

tankabanditka [31]

Answer:

$0.2528$

Explanation:

To calculate the period we need the formula:

$T=\frac{2\pi r^{3/2}}{\sqrt{GM}}$

Where $r$ is the radius of the moon, $G$ is the universal constant of gravitation and $M$ is the mass of mars.

The period of Phobos:

$T_{p}=\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}$

The period of Deimos:

$T_{D}=\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}$

The ratio of the period of Phobos and Deimos:

$\frac{T_{p}}{T_{D}}=\frac{\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}}{\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}}$

$\frac{T_{p}}{T_{D}}=\frac{\sqrt{GM}2\pi r_{p}^{3/2}}{\sqrt{GM}2\pi r_{D}^{3/2}}$

Most terms get canceled and we have:

$\frac{T_{p}}{T_{D}}=\frac{r_{p}^{3/2}}{r_{D}^{3/2}}$

According to the problem

$r_{p}=9,378km\\r_{D}=23,459km$

so the ratio will be:

$\frac{T_{p}}{T_{D}}=\frac{(9,378)^{3/2}}{(23,459)^{3/2}}=\frac{908166.22}{3593058.125}=0.25275$ ≈ $0.2528$

the ratio of the period of revolution of Phobos to that of Deimos is 0.2528

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liberstina [14]

A. supplies energy to make charge flow

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4 years ago