A book weighing 18.0 N is lifted from the floor and placed on a shelf 1.5 m high. What is the minimum amount of work required to
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Answer:
A. 79.3 keV
Explanation:
Because the procedure involves many steps for its resolution and it works faster on paper and pencil, the detailed solution of this exercise is attached as a scanned image of the procedure for review.
In the procedure, the initial values of the problem and the replacement of these values with the correct formulas for this process are taken into account.
Part A. We are given that a car is pushed from rest to a final speed doing 5430 Joules of work. -
To determine the final velocity we will use the work and energy theorem which states that the work done is equal to the change in kinetic energy:
Since the car starts from rest this means that the initial kinetic energy is zero:
The kinetic energy is given by:
Substituting in the formula we get:
Now, we solve for the final velocity. First, we multiply both sides by 2 and divide both sides by the mass:
Now, we take the square root to both sides:
Now, we plug in the values:
Solving the operations:
Therefore, the final velocity is 2.04 m/s.
Part B. Now, we use the following formula for work:
Where "F" is the force and "d" is the distance.
Now, we set this equation equal to the work done by the force:
Now, we divide both sides by the distance "d":
Therefore, the force exerted is 187.2 Newton.
I halved the speed of light in vacuum to get the speed of light in the material, since the speed of light in vacuum is twice the speed of light in material.
The index of refraction is essentially the speed of light through a vacuum divided by the speed of light through given medium.
I attached some notes on refraction too, hopefully this helps :D
The index of refraction is essentially the speed of light through a vacuum divided by the speed of light through given medium.
I attached some notes on refraction too, hopefully this helps :D