Answer:
by subtracting 3 other men
Hello!
To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w
To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.
2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24
Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.
Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.
As our final answer, the width of the pool is 16 feet, and the length is 24 feet.
Hope this helps!
I think it would be 29 students in the larger class
Here is your answer
Given area is
z^2 + 18z + 81
= z^2 + 2× z × 9 + 9^2
[using (a+b)^2= a^2 + 2ab + b^2], we get
= (z+9)^2
we know that area of a square is represented by side^2.
So, here
Side of square is
HOPE IT IS USEFUL
The tunnel is made of two shapes and we can find the volume of each.
Cuboid volume=15×5×30=2250 cu yds.
Half cylinder volume=π(7.5)²30/2=843.75π=2649.38 cu yds.
Total volume=4899.38 cu yds.
