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slamgirl [31]
3 years ago
14

Liệt kê các lỗi có trong chương

Computers and Technology
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

pls mark my brainiest

Explanation:

Create an object of the File class

 Pass it the name of the file to read in quotes

 Then create an object of the Scanner class

 Pass the constructor the new File object

 Then use Scanner methods such as:

 next()

 nextLine()

 hasNextLine()

 hasNext()

 nextDouble()

 nextInt()...

File inputFile = new File("input.txt");

while (in.hasNextLine())

{

String line = in.nextLine();

// Process line;

}

Scanner in = new Scanner(inputFile);

Text File Output

 Create an object of the PrintWriter class

 Pass it the name of the file to write in quotes

• If output.txt exists, it will be emptied

• If output.txt does not exist, it will create an empty file

PrintWriter is an enhanced version of PrintStream

• System.out is a PrintStream object!

PrintWriter out = new PrintWriter("output.txt");

out.println("Hello, World!");

out.printf("Total: %8.2f\n", totalPrice);

System.out.println(“Hello World!”);

 Then use PrintWriter methods such as:

 print()

 println()

 p

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identify at least three additional ethical responsibilities expected from a computer professional. In brief, explain each respon
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The ethical responsibilities for computer professionals are:

Respect Confidentiality.

Maintain professional competence.

Respects and protection of personal privacy.

Explanation:

  • Computer professionals are expected to conduct themselves in an ethical manner.
  • Codes of ethics exist in this field to help these professionals make good decisions about the manner of their professional work.
  • A computer professional must strive to provide the highest quality of work possible by acquiring and maintaining professional competence. He should be knowledgeable in the laws pertaining to his profession and not violate them.
  1. Respect Confidentiality : Confidentiality refers to protecting information from being accessed by unauthorized parties. Only the people who are authorized to do so can gain access to sensitive data. All the security incidents reported in the media today involve major losses of confidentiality.
  2. Maintain professional competence : The capability to perform the duties of one's profession generally, or to perform a particular professional task, with skill of an acceptable quality. Maintaining professional competence allows individuals to learn throughout their career, to develop technical skills, and to keep pace with accountancy changes.
  3. Respects and protection of personal privacy : Privacy computing includes all computing operations by information owners, collectors, publishers, and users during the entire life-cycle of private information, from data generation, sensing, publishing, and dissemination, to data storage, processing, usage, and destruction.

8 0
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PLEASE ILL MARK BRAINLIEST
Minchanka [31]

Answer:

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What is the name for non-paid active links returned by an Internet search engine in the search results?
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Answer:

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Explanation:

7 0
3 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
3 years ago
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