The answer is 7.68.
Hope this helps.
For 49 It's 4*12 and 2*24 and 1*48 and for 64 it's 8*8 and 2*32
It might be k, since 4-4 is 0 and 0 has no absolute value.
Answer:
C
Step-by-step explanation:
Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.
<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>
<em><u /></em>
- Looking at the graph, we can see that the curve doesn't cross an imaginary line at x = 0, this is a vertical asymptote.
- Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.
Looking at the answer choices, the choice C is right.
Let
![I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint%20e%5E%7B-2x%7D%20%5Ccos%282x%29%20%5C%2C%20dx%5B%2F%5Dtex%3C%2Fp%3E%3Cp%3EIntegrate%20by%20parts%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdisplaystyle%20%5Cint%20u%20%5C%2C%20dv%20%3D%20uv%20-%20%5Cint%20v%20%5C%2C%20du)
with
Then
Integrate by parts again, this time with
so that
