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yKpoI14uk [10]
3 years ago
15

The diagram below shows a pendulum in motion.

Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

Potential Energy is given as:

P.E = mgh

which means P.E is directly proportional to height 'h'.

Kinetic Energy is given as:

K.E = (1/2)mv²

which means K.E is directly proportional to velocity 'v²'.

Total Energy of Pendulum = K.E + P.E

1. The pendulum has the most potential energy at extreme position because the height is maximum at the extreme position.

2. The pendulum has the least kinetic energy at extreme position because the velocity is zero at extreme position.

3. The pendulum has most kinetic energy at the mean position because the velocity is maximum at this point.

4. The pendulum has the least potential energy at the mean position because the height is minimum.

A rule to remember: The point where K.E is maximum, P.E is zero at this point and vice versa.Potential Energy is given as:

P.E = mgh

which means P.E is directly proportional to height 'h'.

Kinetic Energy is given as:

K.E = (1/2)mv²

which means K.E is directly proportional to velocity 'v²'.

Total Energy of Pendulum = K.E + P.E

1. The pendulum has the most potential energy at extreme position because the height is maximum at the extreme position.

2. The pendulum has the least kinetic energy at extreme position because the velocity is zero at extreme position.

3. The pendulum has most kinetic energy at the mean position because the velocity is maximum at this point.

4. The pendulum has the least potential energy at the mean position because the height is minimum.

A rule to remember: The point where K.E is maximum, P.E is zero at this point and vice versa.Potential Energy is given as:

P.E = mgh

which means P.E is directly proportional to height 'h'.

Kinetic Energy is given as:

K.E = (1/2)mv²

which means K.E is directly proportional to velocity 'v²'.

Total Energy of Pendulum = K.E + P.E

1. The pendulum has the most potential energy at extreme position because the height is maximum at the extreme position.

2. The pendulum has the least kinetic energy at extreme position because the velocity is zero at extreme position.

3. The pendulum has most kinetic energy at the mean position because the velocity is maximum at this point.

4. The pendulum has the least potential energy at the mean position because the height is minimum.

A rule to remember: The point where K.E is maximum, P.E is zero at this point and vice versa.

Explanation:

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olchik [2.2K]

Answer:

Minimum capacitance = 200 μF

Explanation:

From image B attached, we can calculate the current flowing through the capacitors.

Thus;

Since V=IR; I = V/R = 5/500 = 0.01 A

Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V

So minimum capacitance will be determined from;

i(t) = C(dv/dt)

So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]

C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF

8 0
3 years ago
Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did
Ksivusya [100]

Answer:

40 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:

Workdone = force × distance

Wd = F × s

With the above formula, we can obtain the workdone as follow:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Wd = F × s

Wd = 10 × 4

Wd = 40 J

Thus, 40 J of work was done.

5 0
3 years ago
20 point physics question! :D
Sauron [17]
B, Light, mechanical. The solar panel takes in light energy (from the sun), and in exchange spits out mechanical energy (turns the wheels/powers the battery).
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4 years ago
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A ball is thrown vertically upward with a speed of 1.86
Inessa05 [86]

Answer:

t = 1.09 s.

Explanation:

This is a one-dimensional kinematics question, so the equations of kinematics will be sufficient to solve the question.

y-y_0 = v_0t + \frac{1}{2}at^2\\0 - 3.82 = 1.86t +\frac{1}{2}(-9.8)t^2\\-3.82 = 1.86t - \frac{1}{2}9.8t^2\\4.9t^2 - 1.86t - 3.82 = 0

This quadratic equation can be solved using determinant.

\Delta = b^2 - 4ac\\t_{1,2} = \frac{-b \pm \sqrt{\Delta} }{2a}\\t_1 = 1.09~s\\t_2 = -0.71~s

Of course, we will choose the positive time.

4 0
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