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Lemur [1.5K]
1 year ago
11

In consecutive odd integers, three times the largest integer is fifteen less than two-thirds the smallest integer. find both int

egers. someone help please
Mathematics
1 answer:
aivan3 [116]1 year ago
3 0

Value of both the integers as three times the largest consecutive integer is 15 less than 2/3 the smallest one is -7, -9.

As given,

Let x, x +2 be two consecutive odd integers

Three times largest integer=3( x+2)

15 less than 2/3 smallest integer=(2/3)x -15

Equation :

3(x+2)=(2/ 3)x -15

⇒ 3x +6=(2x -45)/3

⇒ 9x-2x= -18 -45

⇒ 7x=-63

⇒ x =-9

and x+2 =-7

Therefore, value of both the integers as three times the largest consecutive integer is 15 less than the 2/3 the smallest one is -7, -9.

Learn more about integers here

brainly.com/question/15276410

#SPJ4

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The equation for a parabola has the form y=ax2+bx+c, where a, b, and c are constants and a≠0. find an equation for the parabola
IRISSAK [1]

The equation of parabola is

y= ax^2 + bx +c

For point (-1,-9), equation of parabola is

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\\
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For point (-6,-14), equation of parabola is

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So we have three equations , which are

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\\
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Subtracting first two equation will give

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Subtracting second and third equation gives

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back substituting 8 for b and 1 for a, we will get

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So we have

a=1, b=8 and c=-2

Therefore required equation is

y= x^2 +8x-2

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